結果

問題 No.1000 Point Add and Array Add
コンテスト
ユーザー lam6er
提出日時 2025-03-20 20:46:24
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 391 ms / 2,000 ms
コード長 2,403 bytes
コンパイル時間 190 ms
コンパイル使用メモリ 82,320 KB
実行使用メモリ 191,196 KB
最終ジャッジ日時 2025-03-20 20:46:31
合計ジャッジ時間 5,743 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge5
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ファイルパターン 結果
sample AC * 2
other AC * 22
権限があれば一括ダウンロードができます

ソースコード

diff # 

class FenwickTree:
    def __init__(self, size):
        self.n = size
        self.tree = [0] * (self.n + 2)  # 1-based indexing up to size + 1

    def add(self, idx, val):
        while idx <= self.n:
            self.tree[idx] += val
            idx += idx & -idx

    def query(self, idx):
        res = 0
        while idx > 0:
            res += self.tree[idx]
            idx -= idx & -idx
        return res

def main():
    import sys
    input = sys.stdin.read().split()
    ptr = 0
    N = int(input[ptr])
    ptr += 1
    Q = int(input[ptr])
    ptr += 1

    a = list(map(int, input[ptr:ptr + N]))
    ptr += N
    a = [0] + a  # Convert to 1-based index

    queries = []
    diff = [0] * (N + 2)  # For prefix sum to calculate cnt_b

    for time in range(1, Q + 1):
        c = input[ptr]
        ptr += 1
        x = int(input[ptr])
        ptr += 1
        y = int(input[ptr])
        ptr += 1

        if c == 'B':
            queries.append((time, 'B', x, y))
            # Update the difference array for cnt_b
            diff[x] += 1
            if y + 1 <= N:
                diff[y + 1] -= 1
        else:
            queries.append((time, 'A', x, y))

    # Compute cnt_b using the difference array
    cnt_b = [0] * (N + 1)
    current = 0
    for i in range(1, N + 1):
        current += diff[i]
        cnt_b[i] = current

    # Initialize B array with a[i] * cnt_b[i]
    B = [0] * (N + 1)
    for i in range(1, N + 1):
        B[i] = a[i] * cnt_b[i]

    # Prepare events for processing in reverse order
    events = []
    for q in queries:
        if q[1] == 'B':
            t, typ, x, y = q
            events.append((t, 'B', x, y))
        else:
            t, typ, x, y = q
            events.append((t, 'A', x, y))

    # Sort events by descending time; B comes before A at the same time
    events.sort(key=lambda e: (-e[0], 0 if e[1] == 'B' else 1))

    # Process events using Fenwick Tree
    ft = FenwickTree(N + 1)  # Size is N+1 to handle up to N+1

    for event in events:
        if event[1] == 'B':
            x = event[2]
            y = event[3]
            ft.add(x, 1)
            ft.add(y + 1, -1)
        else:
            x = event[2]
            val_y = event[3]
            count = ft.query(x)
            B[x] += val_y * count

    # Output the result for B[1..N]
    print(' '.join(map(str, B[1:N+1])))

if __name__ == "__main__":
    main()
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