結果
| 問題 |
No.1102 Remnants
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-03-20 20:57:44 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 105 ms / 2,000 ms |
| コード長 | 1,824 bytes |
| コンパイル時間 | 297 ms |
| コンパイル使用メモリ | 82,304 KB |
| 実行使用メモリ | 113,464 KB |
| 最終ジャッジ日時 | 2025-03-20 20:57:49 |
| 合計ジャッジ時間 | 4,249 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 25 |
ソースコード
MOD = 10**9 + 7
def main():
import sys
input = sys.stdin.read().split()
idx = 0
N = int(input[idx])
idx +=1
K = int(input[idx])
idx +=1
A = list(map(int, input[idx:idx+N]))
max_m = 2 * 10**5 # since N can be up to 2e5, m_left = i-1 and m_right = N-i can each be up to 2e5-1
# Precompute factorial and inverse factorial up to max_m
fact = [1] * (max_m +1)
for i in range(1, max_m +1):
fact[i] = fact[i-1] * i % MOD
inv_fact = [1] * (max_m +1)
inv_fact[max_m] = pow(fact[max_m], MOD-2, MOD)
for i in range(max_m -1, -1, -1):
inv_fact[i] = inv_fact[i+1] * (i+1) % MOD
# Precompute left_part = product_{j=1 to m} (K +j) mod MOD
max_part = max_m # enough for both left and right parts as m_left and m_right are up to N<=2e5
left_part = [1] * (max_part +2)
for m in range(1, max_part +1):
term = (K % MOD + m) % MOD
left_part[m] = left_part[m-1] * term % MOD
# Compute the answer
ans = 0
for i in range(1, N+1):
# Calculate left contribution
m_left = i-1
if m_left ==0:
left = 1 % MOD
elif m_left > max_part:
left = 1
else:
if m_left <0:
left = 1
else:
left = left_part[m_left] * inv_fact[m_left] % MOD
# Calculate right contribution
m_right = N -i
if m_right ==0:
right = 1 % MOD
elif m_right > max_part:
right =1
else:
if m_right <0:
right =1
else:
right = left_part[m_right] * inv_fact[m_right] % MOD
total = left * right % MOD
ans = (ans + A[i-1] * total) % MOD
print(ans % MOD)
if __name__ == '__main__':
main()
lam6er