結果
問題 | No.1094 木登り / Climbing tree |
ユーザー |
![]() |
提出日時 | 2025-03-20 21:00:47 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 983 ms / 2,000 ms |
コード長 | 1,791 bytes |
コンパイル時間 | 295 ms |
コンパイル使用メモリ | 82,396 KB |
実行使用メモリ | 215,520 KB |
最終ジャッジ日時 | 2025-03-20 21:01:16 |
合計ジャッジ時間 | 24,286 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 26 |
ソースコード
import sysfrom collections import dequedef main():sys.setrecursionlimit(1 << 25)input = sys.stdin.read().split()ptr = 0n = int(input[ptr])ptr +=1adj = [[] for _ in range(n+1)]for _ in range(n-1):a = int(input[ptr])b = int(input[ptr+1])c = int(input[ptr+2])ptr +=3adj[a].append( (b, c) )adj[b].append( (a, c) )LOG = 20parent = [0]*(n+1)depth = [0]*(n+1)distance = [0]*(n+1)root =1parent[root] =0q = deque([root])while q:u = q.popleft()for v, w in adj[u]:if parent[u] == v:continueif parent[v] ==0 and v != root:parent[v] =udepth[v] = depth[u]+1distance[v] = distance[u] + wq.append(v)up = [[0]*(n+1) for _ in range(LOG)]for u in range(1, n+1):up[0][u] = parent[u]for k in range(1, LOG):for u in range(1, n+1):up[k][u] = up[k-1][up[k-1][u]]def lca(u, v):if depth[u] < depth[v]:u, v = v, ufor k in range(LOG-1, -1, -1):if depth[u] - (1 << k) >= depth[v]:u = up[k][u]if u ==v:return ufor k in range(LOG-1, -1, -1):if up[k][u] != up[k][v]:u = up[k][u]v = up[k][v]return up[0][u]q_num = int(input[ptr])ptr +=1output = []for _ in range(q_num):s = int(input[ptr])t = int(input[ptr+1])ptr +=2lca_node = lca(s, t)res = distance[s] + distance[t] - 2 * distance[lca_node]output.append(str(res))print('\n'.join(output))if __name__ == '__main__':main()