結果
問題 |
No.1094 木登り / Climbing tree
|
ユーザー |
![]() |
提出日時 | 2025-03-20 21:00:47 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 983 ms / 2,000 ms |
コード長 | 1,791 bytes |
コンパイル時間 | 295 ms |
コンパイル使用メモリ | 82,396 KB |
実行使用メモリ | 215,520 KB |
最終ジャッジ日時 | 2025-03-20 21:01:16 |
合計ジャッジ時間 | 24,286 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 26 |
ソースコード
import sys from collections import deque def main(): sys.setrecursionlimit(1 << 25) input = sys.stdin.read().split() ptr = 0 n = int(input[ptr]) ptr +=1 adj = [[] for _ in range(n+1)] for _ in range(n-1): a = int(input[ptr]) b = int(input[ptr+1]) c = int(input[ptr+2]) ptr +=3 adj[a].append( (b, c) ) adj[b].append( (a, c) ) LOG = 20 parent = [0]*(n+1) depth = [0]*(n+1) distance = [0]*(n+1) root =1 parent[root] =0 q = deque([root]) while q: u = q.popleft() for v, w in adj[u]: if parent[u] == v: continue if parent[v] ==0 and v != root: parent[v] =u depth[v] = depth[u]+1 distance[v] = distance[u] + w q.append(v) up = [[0]*(n+1) for _ in range(LOG)] for u in range(1, n+1): up[0][u] = parent[u] for k in range(1, LOG): for u in range(1, n+1): up[k][u] = up[k-1][up[k-1][u]] def lca(u, v): if depth[u] < depth[v]: u, v = v, u for k in range(LOG-1, -1, -1): if depth[u] - (1 << k) >= depth[v]: u = up[k][u] if u ==v: return u for k in range(LOG-1, -1, -1): if up[k][u] != up[k][v]: u = up[k][u] v = up[k][v] return up[0][u] q_num = int(input[ptr]) ptr +=1 output = [] for _ in range(q_num): s = int(input[ptr]) t = int(input[ptr+1]) ptr +=2 lca_node = lca(s, t) res = distance[s] + distance[t] - 2 * distance[lca_node] output.append(str(res)) print('\n'.join(output)) if __name__ == '__main__': main()