結果

問題 No.2419 MMA文字列2
ユーザー lam6er
提出日時 2025-03-20 21:06:17
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 187 ms / 2,000 ms
コード長 941 bytes
コンパイル時間 167 ms
コンパイル使用メモリ 82,472 KB
実行使用メモリ 132,996 KB
最終ジャッジ日時 2025-03-20 21:06:24
合計ジャッジ時間 4,382 ms
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 30
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

S = input().strip()
n = len(S)
if n < 3:
print(0)
exit()
# Initialize suffix array where suffix[i][c] is the count of character c from position i to end
suffix = [[0] * 26 for _ in range(n + 2)] # suffix[n] and beyond are all zeros
for i in range(n-1, -1, -1):
current_char = S[i]
num = ord(current_char) - ord('A')
# Copy the suffix counts from i+1 to i
for k in range(26):
suffix[i][k] = suffix[i+1][k]
# Increment the current character count
suffix[i][num] += 1
prefix_counts = [0] * 26
total = 0
for j in range(n):
current_char = S[j]
num = ord(current_char) - ord('A')
a = prefix_counts[num]
# Calculate the number of valid Y characters after position j
if j + 1 < n:
y_count = (n - j - 1) - suffix[j + 1][num]
else:
y_count = 0
total += a * y_count
# Update the prefix count for the current character
prefix_counts[num] += 1
print(total)
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0