結果

問題 No.1073 無限すごろく
ユーザー lam6er
提出日時 2025-03-20 21:08:27
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 43 ms / 2,000 ms
コード長 2,044 bytes
コンパイル時間 192 ms
コンパイル使用メモリ 82,396 KB
実行使用メモリ 61,996 KB
最終ジャッジ日時 2025-03-20 21:09:19
合計ジャッジ時間 2,421 ms
ジャッジサーバーID
(参考情報)
judge1 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 30
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

MOD = 10**9 + 7
def main():
N = int(input())
if N == 0:
print(1)
return
inv6 = pow(6, MOD-2, MOD)
p = [0] * 6
p[0] = 1 % MOD
if N < 6:
for i in range(1, N + 1):
total = 0
for k in range(1, 7):
if i - k >= 0:
total = (total + p[i - k]) % MOD
p[i] = (total * inv6) % MOD
print(p[N])
return
# Compute p[0] to p[5]
p = [0] * 6
p[0] = 1 % MOD
for i in range(1, 6):
total = 0
for k in range(1, 7):
if i - k >= 0:
total = (total + p[i - k]) % MOD
p[i] = (total * inv6) % MOD
def multiply_matrices(a, b):
res = [[0] * 6 for _ in range(6)]
for i in range(6):
for j in range(6):
for k in range(6):
res[i][j] = (res[i][j] + a[i][k] * b[k][j]) % MOD
return res
def multiply_vector(mat, vec):
res = [0] * 6
for i in range(6):
for j in range(6):
res[i] = (res[i] + mat[i][j] * vec[j]) % MOD
return res
def matrix_pow(mat, power):
result = [[0] * 6 for _ in range(6)]
for i in range(6):
result[i][i] = 1 # Identity matrix
while power > 0:
if power % 2 == 1:
result = multiply_matrices(result, mat)
mat = multiply_matrices(mat, mat)
power //= 2
return result
# Create the transition matrix
def create_matrix(inv6):
mat = [[0] * 6 for _ in range(6)]
for j in range(6):
mat[0][j] = inv6
for i in range(1, 6):
mat[i][i-1] = 1
return mat
mat = create_matrix(inv6)
exponent = N - 5
mat_pow = matrix_pow(mat, exponent)
initial_vector = [p[5], p[4], p[3], p[2], p[1], p[0]]
final_vector = multiply_vector(mat_pow, initial_vector)
print(final_vector[0])
if __name__ == "__main__":
main()
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