結果

問題 No.622 点と三角柱の内外判定
ユーザー lam6er
提出日時 2025-03-20 21:11:06
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 37 ms / 1,500 ms
コード長 1,730 bytes
コンパイル時間 170 ms
コンパイル使用メモリ 82,444 KB
実行使用メモリ 53,988 KB
最終ジャッジ日時 2025-03-20 21:11:20
合計ジャッジ時間 2,224 ms
ジャッジサーバーID
(参考情報)
judge4 / judge3
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ファイルパターン 結果
other AC * 32
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ソースコード

diff #
プレゼンテーションモードにする

ax, ay, az = map(int, input().split())
bx, by, bz = map(int, input().split())
cx, cy, cz = map(int, input().split())
dx, dy, dz = map(int, input().split())
# Calculate vectors AB and AC
ab = (bx - ax, by - ay, bz - az)
ac = (cx - ax, cy - ay, cz - az)
# Compute the normal vector (cross product AB x AC)
n = (
ab[1] * ac[2] - ab[2] * ac[1],
ab[2] * ac[0] - ab[0] * ac[2],
ab[0] * ac[1] - ab[1] * ac[0]
)
# Compute the projection of D onto the plane ABC
denominator = n[0]**2 + n[1]**2 + n[2]**2
if denominator == 0:
print("NO")
exit()
n_dot = n[0] * (ax - dx) + n[1] * (ay - dy) + n[2] * (az - dz)
t = n_dot / denominator
px = dx + t * n[0]
py = dy + t * n[1]
pz = dz + t * n[2]
# Calculate vectors AP, AB, AC
ap = (px - ax, py - ay, pz - az)
ab = (bx - ax, by - ay, bz - az)
ac_vec = (cx - ax, cy - ay, cz - az)
# Determine the best pair of components to compute barycentric coordinates
det_xy = ab[0] * ac_vec[1] - ab[1] * ac_vec[0]
det_yz = ab[1] * ac_vec[2] - ab[2] * ac_vec[1]
det_zx = ab[2] * ac_vec[0] - ab[0] * ac_vec[2]
max_det = max(abs(det_xy), abs(det_yz), abs(det_zx))
if max_det == 0:
print("NO")
exit()
if max_det == abs(det_xy):
a = ab[0]
b = ac_vec[0]
c = ap[0]
d = ab[1]
e = ac_vec[1]
f = ap[1]
det = det_xy
elif max_det == abs(det_yz):
a = ab[1]
b = ac_vec[1]
c = ap[1]
d = ab[2]
e = ac_vec[2]
f = ap[2]
det = det_yz
else:
a = ab[2]
b = ac_vec[2]
c = ap[2]
d = ab[0]
e = ac_vec[0]
f = ap[0]
det = det_zx
s = (e * c - b * f) / det
t_val = (a * f - d * c) / det
epsilon = 1e-10
if s >= -epsilon and t_val >= -epsilon and (s + t_val) <= 1.0 + epsilon:
print("YES")
else:
print("NO")
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