結果
問題 | No.622 点と三角柱の内外判定 |
ユーザー |
![]() |
提出日時 | 2025-03-20 21:11:06 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 37 ms / 1,500 ms |
コード長 | 1,730 bytes |
コンパイル時間 | 170 ms |
コンパイル使用メモリ | 82,444 KB |
実行使用メモリ | 53,988 KB |
最終ジャッジ日時 | 2025-03-20 21:11:20 |
合計ジャッジ時間 | 2,224 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
other | AC * 32 |
ソースコード
ax, ay, az = map(int, input().split())bx, by, bz = map(int, input().split())cx, cy, cz = map(int, input().split())dx, dy, dz = map(int, input().split())# Calculate vectors AB and ACab = (bx - ax, by - ay, bz - az)ac = (cx - ax, cy - ay, cz - az)# Compute the normal vector (cross product AB x AC)n = (ab[1] * ac[2] - ab[2] * ac[1],ab[2] * ac[0] - ab[0] * ac[2],ab[0] * ac[1] - ab[1] * ac[0])# Compute the projection of D onto the plane ABCdenominator = n[0]**2 + n[1]**2 + n[2]**2if denominator == 0:print("NO")exit()n_dot = n[0] * (ax - dx) + n[1] * (ay - dy) + n[2] * (az - dz)t = n_dot / denominatorpx = dx + t * n[0]py = dy + t * n[1]pz = dz + t * n[2]# Calculate vectors AP, AB, ACap = (px - ax, py - ay, pz - az)ab = (bx - ax, by - ay, bz - az)ac_vec = (cx - ax, cy - ay, cz - az)# Determine the best pair of components to compute barycentric coordinatesdet_xy = ab[0] * ac_vec[1] - ab[1] * ac_vec[0]det_yz = ab[1] * ac_vec[2] - ab[2] * ac_vec[1]det_zx = ab[2] * ac_vec[0] - ab[0] * ac_vec[2]max_det = max(abs(det_xy), abs(det_yz), abs(det_zx))if max_det == 0:print("NO")exit()if max_det == abs(det_xy):a = ab[0]b = ac_vec[0]c = ap[0]d = ab[1]e = ac_vec[1]f = ap[1]det = det_xyelif max_det == abs(det_yz):a = ab[1]b = ac_vec[1]c = ap[1]d = ab[2]e = ac_vec[2]f = ap[2]det = det_yzelse:a = ab[2]b = ac_vec[2]c = ap[2]d = ab[0]e = ac_vec[0]f = ap[0]det = det_zxs = (e * c - b * f) / dett_val = (a * f - d * c) / detepsilon = 1e-10if s >= -epsilon and t_val >= -epsilon and (s + t_val) <= 1.0 + epsilon:print("YES")else:print("NO")