結果
| 問題 |
No.1286 Stone Skipping
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-03-20 21:11:40 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 49 ms / 2,000 ms |
| コード長 | 1,514 bytes |
| コンパイル時間 | 154 ms |
| コンパイル使用メモリ | 82,348 KB |
| 実行使用メモリ | 62,976 KB |
| 最終ジャッジ日時 | 2025-03-20 21:12:26 |
| 合計ジャッジ時間 | 2,574 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 26 |
ソースコード
def find_min_x(D):
min_x = float('inf')
max_k = 60 # Sufficiently large upper bound for k
for k in range(max_k + 1):
low = 1
high = 2 * D
best = None
# Binary search for x in [1, 2D] that satisfies the sum condition
while low <= high:
mid = (low + high) // 2
current_sum = 0
current_x = mid
for _ in range(k + 1):
current_sum += current_x
current_x = current_x // 2
if current_x == 0:
break # Further terms are zero, so break early
if current_sum == D:
best = mid
high = mid - 1 # Try to find a smaller x
elif current_sum < D:
low = mid + 1
else:
high = mid - 1
# After binary search, check if low is a solution
if low <= 2 * D:
current_sum = 0
current_x = low
for _ in range(k + 1):
current_sum += current_x
current_x = current_x // 2
if current_x == 0:
break
if current_sum == D:
if best is None or low < best:
best = low
# Update the minimum x if a valid x is found
if best is not None and best < min_x:
min_x = best
return min_x if min_x != float('inf') else D
# Read input and output the result
D = int(input())
print(find_min_x(D))
lam6er