結果

問題 No.2402 Dirty Stairs and Shoes
ユーザー lam6er
提出日時 2025-03-20 21:19:17
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 225 ms / 2,000 ms
コード長 1,896 bytes
コンパイル時間 160 ms
コンパイル使用メモリ 82,112 KB
実行使用メモリ 111,264 KB
最終ジャッジ日時 2025-03-20 21:20:28
合計ジャッジ時間 5,006 ms
ジャッジサーバーID
(参考情報)
judge2 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 32
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
from collections import deque
def main():
n, K = map(int, sys.stdin.readline().split())
m1 = int(sys.stdin.readline())
a_list = list(map(int, sys.stdin.readline().split())) if m1 > 0 else []
dirty = set(a_list)
m2 = int(sys.stdin.readline())
b_list = list(map(int, sys.stdin.readline().split())) if m2 > 0 else []
mat = set(b_list)
# Visited arrays for clean and dirty states
visited_clean = [False] * (n + 1)
visited_dirty = [False] * (n + 1)
queue = deque()
queue.append((0, True))
visited_clean[0] = True
found = False
while queue:
p, is_clean = queue.popleft()
for move in [1, K]:
next_p = p + move
if next_p > n:
continue
# Check if next_p is the target N
if next_p == n:
# The new state is same as current since N is neither dirty nor mat
if is_clean:
found = True
break
else:
continue
else:
# Determine the new state based on next_p's type
if next_p in dirty:
new_clean = False
elif next_p in mat:
new_clean = True
else:
new_clean = is_clean
# Check if this state has been visited before
if new_clean:
if not visited_clean[next_p]:
visited_clean[next_p] = True
queue.append((next_p, new_clean))
else:
if not visited_dirty[next_p]:
visited_dirty[next_p] = True
queue.append((next_p, new_clean))
if found:
break
print("Yes" if found else "No")
if __name__ == "__main__":
main()
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