結果

問題 No.1100 Boxes
ユーザー lam6er
提出日時 2025-03-20 21:22:42
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 202 ms / 2,000 ms
コード長 1,422 bytes
コンパイル時間 219 ms
コンパイル使用メモリ 82,372 KB
実行使用メモリ 67,408 KB
最終ジャッジ日時 2025-03-20 21:22:49
合計ジャッジ時間 4,983 ms
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 36
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

MOD = 998244353
def main():
import sys
input = sys.stdin.read().split()
N = int(input[0])
K = int(input[1])
if K == 0:
print(0)
return
# Precompute inverses of 1..K
inv = [1] * (K + 1)
for i in range(1, K + 1):
inv[i] = pow(i, MOD - 2, MOD)
# Compute combination numbers C(K, j) for j in 0..K
comb = [0] * (K + 1)
comb[0] = 1
for j in range(1, K + 1):
comb[j] = comb[j-1] * (K - j + 1) % MOD
comb[j] = comb[j] * inv[j] % MOD
# Precompute pow_val[j] = (K - j)^N mod MOD
pow_val = [0] * (K + 1)
for j in range(K + 1):
m = K - j
if m == 0:
pow_val[j] = 0
else:
pow_val[j] = pow(m, N, MOD)
# Precompute power_of_minus_two: (-2)^j mod MOD
power_minus_two = [1] * (K + 1)
minus_two = MOD - 2
for j in range(1, K + 1):
power_minus_two[j] = power_minus_two[j - 1] * minus_two % MOD
# Compute sum_terms
sum_terms = 0
for j in range(K + 1):
term = comb[j] * pow_val[j] % MOD
term = term * power_minus_two[j] % MOD
sum_terms = (sum_terms + term) % MOD
# Compute K^N mod MOD
pow_k_n = pow(K, N, MOD)
# Compute the answer
ans = (pow_k_n - sum_terms) % MOD
inv_2 = pow(2, MOD - 2, MOD)
ans = ans * inv_2 % MOD
print(ans)
if __name__ == '__main__':
main()
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