結果
| 問題 |
No.3073 Fraction Median
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2025-03-24 19:28:49 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 2,404 ms / 2,500 ms |
| コード長 | 4,909 bytes |
| コンパイル時間 | 1,231 ms |
| コンパイル使用メモリ | 119,088 KB |
| 実行使用メモリ | 10,452 KB |
| 最終ジャッジ日時 | 2025-03-24 19:29:30 |
| 合計ジャッジ時間 | 34,052 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 18 |
ソースコード
#include <iostream>
#include <sstream>
#include <cstring>
#include <string>
#include <algorithm>
#include <cmath>
#include <map>
#include <set>
#include <vector>
#include <queue>
#include <unordered_set>
#include <unordered_map>
#include <bitset>
#include <ctime>
#include <assert.h>
#include <deque>
#include <list>
#include <stack>
#include <numeric>
#include <iomanip>
using namespace std;
typedef pair<long long, int> pli;
typedef pair<int, long long> pil;
typedef pair<long long , long long> pll;
typedef pair<int, int> pii;
typedef pair<double, double> pdd;
typedef pair<int, pii> piii;
typedef pair<int, long long > pil;
typedef pair<long long, pii> plii;
typedef pair<double, int> pdi;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<ull, ull> puu;
// typedef long double ld;
typedef double ld;
const int N = 2000086, MOD = 998244353, INF = 0x3f3f3f3f, MID = 333;
const long double EPS = 1e-9;
int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1};
// int dx[8] = {1, 1, 0, -1, -1, -1, 0, 1}, dy[8] = {0, 1, 1, 1, 0, -1, -1, -1};
// int dx[8] = {2, 1, -1, -2, -2, -1, 1, 2}, dy[8] = {1, 2, 2, 1, -1, -2, -2, -1};
int n, m, cnt;
int w[N];
vector<ll> num;
ll res;
ll lowbit(ll x) { return x & -x; }
ll lcm(ll a, ll b) { return a / __gcd(a, b) * b; }
inline double rand(double l, double r) { return (double)rand() / RAND_MAX * (r - l) + l; }
inline ll qmi(ll a, ll b, ll c) { ll res = 1; while (b) { if (b & 1) res = res * a % c; a = a * a % c; b >>= 1; } return res; }
inline ll qmi(ll a, ll b) { ll res = 1; while (b) { if (b & 1) res *= a; a *= a; b >>= 1; } return res; }
inline double qmi(double a, ll b) { double res = 1; while (b) { if (b & 1) res *= a; a *= a; b >>= 1; } return res; }
inline ll C(ll a, ll b, int* c) { if (a < b) return 0; ll res = 1; for (ll j = a, i = 1; i < b + 1; i++, j--) res *= j; for (ll j = a, i = 1; i < b + 1; i++, j--) res /= i; return res; }
inline int find_(int x) { return lower_bound(num.begin(), num.end(), x) - num.begin(); }
bool check(ld mid) {
ll c = 0, t = (ll)n * (n - 1) / 2 - 1;
for (int i = 1; i <= n; i++) {
if (mid <= 1) {
if (i == n || (ld)w[i] / w[n] >= mid) continue;
int l = i + 1, r = n;
while (l < r) {
int m = l + r >> 1;
ld v = (ld)w[i] / w[m];
if (v < mid) r = m;
else l = m + 1;
}
c += n - l + 1;
} else {
c += n - i;
if (i == 1 || (ld)w[i] / w[i - 1] >= mid) continue;
int l = 1, r = i - 1;
while (l < r) {
int m = l + r >> 1;
ld v = (ld)w[i] / w[m];
if (v < mid) r = m;
else l = m + 1;
}
c += i - 1 - l + 1;
}
if (c > t) return 0;
}
return c <= t;
}
char *p1,*p2,buf[100000];
#define nc() (p1==p2 && (p2=(p1=buf)+fread(buf,1,100000,stdin),p1==p2)?EOF:*p1++)
int read()
{
int x=0,f=1;
char ch=nc();
while(ch<48||ch>57)
{
if(ch=='-')
f=-1;
ch=nc();
}
while(ch>=48&&ch<=57)
x=x*10+ch-48,ch=nc();
return x*f;
}
int main() {
cin >> n;
for (int i = 1; i < n + 1; i++) w[i] = read();
sort(w + 1, w + n + 1);
ld pl = 0, pr = 1.1;
while (abs(pr - pl) > EPS) {
ld mid = (pl + pr) / 2;
if (check(mid)) pl = mid;
else pr = mid;
}
if (abs(pl - 1) < EPS) {
puts("1 1");
return 0;
}
if (pl < 1) {
for (int i = n; i; i--) {
int l = 1, r = i - 1;
while (l < r) {
int mid = l + r + 1 >> 1;
ld v = (ld)w[mid] / w[i];
if (v <= pl) l = mid;
else r = mid - 1;
}
if (abs((ld)w[l] / w[i] - pl) < EPS) {
int g = __gcd(w[l], w[i]);
printf("%d %d\n", w[l], w[i]);
return 0;
}
if (l != i && abs((ld)w[l + 1] / w[i] - pl) < EPS) {
int g = __gcd(w[l + 1], w[i]);
printf("%d %d\n", w[l + 1], w[i]);
return 0;
}
}
} else {
for (int i = n; i; i--) {
int l = 1, r = i - 1;
while (l < r) {
int mid = l + r + 1 >> 1;
ld v = (ld)w[i] / w[mid];
if (v >= pl) l = mid;
else r = mid - 1;
}
if (abs((ld)w[i] / w[l] - pl) < EPS) {
int g = __gcd(w[l], w[i]);
printf("%d %d\n", w[i], w[l]);
return 0;
}
if (l != i && abs((ld)w[i] / w[l + 1] - pl) < EPS) {
int g = __gcd(w[l + 1], w[i]);
printf("%d %d\n", w[i], w[l + 1]);
return 0;
}
}
}
// cout << pl << endl;
return 0;
}