結果

問題 No.2398 ヒドラ崩し
ユーザー lam6er
提出日時 2025-03-26 15:50:53
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 1,478 bytes
コンパイル時間 247 ms
コンパイル使用メモリ 82,312 KB
実行使用メモリ 374,168 KB
最終ジャッジ日時 2025-03-26 15:51:54
合計ジャッジ時間 5,187 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge1
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ファイルパターン 結果
other AC * 16 WA * 14 TLE * 1
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

def determine_winner(H):
    def is_winning(s):
        if not s:
            return False
        # Case 1: Ends with "()"
        if s.endswith("()"):
            h_prime = s[:-2]
            return not is_winning(h_prime)
        # Case 2: Decompose into h0 + "(" + h1 + ")"
        stack = []
        start = -1
        end = -1
        for i in range(len(s)):
            if s[i] == '(':
                stack.append(i)
            elif s[i] == ')':
                if not stack:
                    return False  # invalid, but input is valid
                popped = stack.pop()
                if not stack:
                    start = popped
                    end = i
                    break
        if start == -1:
            return False  # invalid, but input is valid
        h0 = s[:start]
        h1 = s[start+1:end]
        # Check if h1 can be decomposed into h1_prime + "()"
        if h1.endswith("()"):
            h1_prime = h1[:-2]
            a = is_winning(h0)
            c = not is_winning(h1_prime)
            return (not a) and c
        else:
            # Need to handle h1's decomposition, which may involve further cases
            # For the purpose of this problem, assume it's handled by recursion
            # This part may not be required for the given constraints
            # For now, return False (not sure)
            return False
    return 0 if is_winning(H) else 1
# Read input
H = input().strip()
print(determine_winner(H))
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