結果
問題 |
No.822 Bitwise AND
|
ユーザー |
![]() |
提出日時 | 2025-03-26 15:52:50 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,787 bytes |
コンパイル時間 | 303 ms |
コンパイル使用メモリ | 82,148 KB |
実行使用メモリ | 63,476 KB |
最終ジャッジ日時 | 2025-03-26 15:53:31 |
合計ジャッジ時間 | 1,918 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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ファイルパターン | 結果 |
---|---|
other | AC * 12 WA * 5 |
ソースコード
import sys from functools import lru_cache def main(): N, K = map(int, sys.stdin.readline().split()) if N == 0: if K >= 1: print("INF") else: print(1) return # Collect the positions of 0 bits in N (sorted from highest to lowest) bits = [] mask = ~N for i in reversed(range(20)): # Check up to 20 bits if (mask >> i) & 1: bits.append(i) bits = sorted(bits, reverse=True) # Process highest bits first if not bits: print(1 if K >= 0 else 0) return # Precompute the maximum possible addition from remaining bits max_add = [0] * (len(bits) + 1) for i in range(len(bits)-1, -1, -1): max_add[i] = max_add[i+1] + (1 << bits[i]) @lru_cache(maxsize=None) def dfs(pos, delta, state): if pos == len(bits): return 1 if 0 <= delta <= K else 0 current_bit = bits[pos] sum_rest = max_add[pos+1] total = 0 # Option 1: Set bit in a (only if state is 'lt') if state == 1: # state 1 is 'lt' new_d = delta - (1 << current_bit) if new_d <= K: total += dfs(pos + 1, new_d, 1) # Option 2: Set bit in b new_d = delta + (1 << current_bit) new_state = state if state == 0: # state 0 is 'eq' new_state = 1 # Check if adding remaining bits could exceed K if new_d + sum_rest <= K: total += dfs(pos + 1, new_d, new_state) elif new_d <= K: total += dfs(pos + 1, new_d, new_state) # Option 3: Do not set the bit total += dfs(pos + 1, delta, state) return total result = dfs(0, 0, 0) print(result) if __name__ == "__main__": main()