結果

問題 No.1290 Addition and Subtraction Operation
ユーザー lam6er
提出日時 2025-03-26 15:53:33
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 2,546 bytes
コンパイル時間 242 ms
コンパイル使用メモリ 82,236 KB
実行使用メモリ 127,108 KB
最終ジャッジ日時 2025-03-26 15:54:32
合計ジャッジ時間 18,703 ms
ジャッジサーバーID
(参考情報)
judge2 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 70 WA * 15
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
class FenwickTree:
def __init__(self, size):
self.n = size
self.tree = [0] * (self.n + 2) # 1-based indexing
def add(self, idx, delta):
while idx <= self.n:
self.tree[idx] += delta
idx += idx & -idx
def query(self, idx):
res = 0
while idx > 0:
res += self.tree[idx]
idx -= idx & -idx
return res
def main():
input = sys.stdin.read().split()
ptr = 0
N = int(input[ptr])
ptr += 1
M = int(input[ptr])
ptr += 1
B = list(map(int, input[ptr:ptr+N]))
ptr += N
operations = []
for _ in range(M):
L = int(input[ptr])
ptr += 1
R = int(input[ptr])
ptr += 1
operations.append((L, R))
# Sort operations in decreasing order of R, then decreasing L
operations.sort(key=lambda x: (-x[1], -x[0]))
max_size = N + 2
even_tree = FenwickTree(max_size)
odd_tree = FenwickTree(max_size)
for (L, R) in operations:
# Compute K_i
current_R = R
# Query the current contribution
if current_R % 2 == 0:
contrib = even_tree.query(current_R)
else:
contrib = odd_tree.query(current_R)
original_B = B[current_R - 1]
current_B_R = original_B - contrib
# Compute exponent R - L
exponent = current_R - L
sign = 1 if (exponent % 2 == 0) else -1
K_i = current_B_R * sign
# Compute C_i = K_i * (-1)^L
L_parity = L % 2
c_sign = -1 if L_parity else 1
C_i = K_i * c_sign
# Apply range update to even and odd trees
# Even positions in [L, R]
start_even = L if (L % 2 == 0) else L + 1
end_even = R if (R % 2 == 0) else R - 1
if start_even <= end_even:
even_tree.add(start_even, C_i)
even_tree.add(end_even + 1, -C_i)
# Odd positions in [L, R]
start_odd = L if (L % 2 == 1) else L + 1
end_odd = R if (R % 2 == 1) else R - 1
if start_odd <= end_odd:
odd_tree.add(start_odd, -C_i)
odd_tree.add(end_odd + 1, C_i)
# Check all positions
all_zero = True
for j in range(1, N + 1):
if j % 2 == 0:
contrib = even_tree.query(j)
else:
contrib = odd_tree.query(j)
original = B[j - 1]
if original - contrib != 0:
all_zero = False
break
print("YES" if all_zero else "NO")
if __name__ == "__main__":
main()
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