結果

問題 No.1826 Fruits Collecting
ユーザー lam6er
提出日時 2025-03-26 15:55:29
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 951 ms / 2,000 ms
コード長 2,083 bytes
コンパイル時間 343 ms
コンパイル使用メモリ 82,752 KB
実行使用メモリ 155,736 KB
最終ジャッジ日時 2025-03-26 15:56:39
合計ジャッジ時間 21,583 ms
ジャッジサーバーID
(参考情報)
judge2 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 43
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import bisect
def main():
import sys
input = sys.stdin.read
data = input().split()
idx = 0
N = int(data[idx])
idx += 1
fruits = []
for _ in range(N):
T = int(data[idx])
X = int(data[idx+1])
V = int(data[idx+2])
idx += 3
if T >= abs(X):
a = T + X
b = T - X
fruits.append((a, b, V))
if not fruits:
print(0)
return
# Sort by 'a', then by 'b'
fruits.sort(key=lambda x: (x[0], x[1]))
# Compress 'b' values
b_values = [b for (a, b, v) in fruits]
b_sorted = sorted(list(set(b_values)))
max_b = len(b_sorted)
# Fenwick Tree for maximum
class FenwickTreeMax:
def __init__(self, size):
self.n = size
self.tree = [-float('inf')] * (self.n + 2) # 1-based
def update(self, idx, value):
while idx <= self.n:
if value > self.tree[idx]:
self.tree[idx] = value
else:
break # No need to proceed further
idx += idx & -idx
def query(self, idx):
res = -float('inf')
while idx > 0:
if self.tree[idx] > res:
res = self.tree[idx]
idx -= idx & -idx
return res
# Compress the b values to indices starting from 1
ft = FenwickTreeMax(len(b_sorted))
max_value = 0
for a, b, v in fruits:
pos = bisect.bisect_left(b_sorted, b) + 1 # 1-based index
current_max = ft.query(pos)
if current_max == -float('inf'):
current_max = 0
current_dp = current_max + v
if current_dp > max_value:
max_value = current_dp
# Update the Fenwick tree if this is better than the existing value at pos
existing = ft.query(pos) # Current max up to pos
if current_dp > existing:
ft.update(pos, current_dp)
print(max_value)
if __name__ == '__main__':
main()
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