結果
| 問題 | No.1053 ゲーミング棒 |
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-03-26 15:58:54 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 139 ms / 2,000 ms |
| コード長 | 1,632 bytes |
| コンパイル時間 | 171 ms |
| コンパイル使用メモリ | 82,644 KB |
| 実行使用メモリ | 123,692 KB |
| 最終ジャッジ日時 | 2025-03-26 15:59:45 |
| 合計ジャッジ時間 | 3,872 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 34 |
ソースコード
import sys
from collections import defaultdict
def main():
N = int(sys.stdin.readline())
A = list(map(int, sys.stdin.readline().split()))
count = defaultdict(int)
last = {}
for i in range(N):
c = A[i]
count[c] += 1
last[c] = i # 0-based
# Sort colors based on their last occurrence
sorted_colors = sorted(last.keys(), key=lambda x: last[x])
# Construct the target array T
T = []
for c in sorted_colors:
T.extend([c] * count[c])
if T == A:
print(0)
return
# Check if T is a cyclic shift of A (i.e., exists in A + A)
s = A + A
pattern = T
len_pat = len(pattern)
len_text = len(s)
# KMP algorithm to check if pattern is a substring of s
# Build prefix array (LPS)
lps = [0] * len_pat
length = 0 # length of the previous longest prefix suffix
i = 1
while i < len_pat:
if pattern[i] == pattern[length]:
length += 1
lps[i] = length
i += 1
else:
if length != 0:
length = lps[length - 1]
else:
lps[i] = 0
i += 1
# Search using KMP
i = j = 0
found = False
while i < len_text:
if s[i] == pattern[j]:
i += 1
j += 1
if j == len_pat:
found = True
break
else:
if j != 0:
j = lps[j - 1]
else:
i += 1
if found:
print(1)
else:
print(-1)
if __name__ == "__main__":
main()
lam6er