#1060652 (PyPy3) No.3075 Mex Recurrence Formula

• 問題: No.3075 Mex Recurrence Formula
• ユーザー: mkawa2
• 提出日時: 2025-03-28 22:10:13
• 言語: PyPy3 (7.3.15)
• 結果: WA
• 実行時間: -
• コード長: 5,644 bytes
• コンパイル時間: 324 ms
• コンパイル使用メモリ: 82,288 KB
• 実行使用メモリ: 156,792 KB
• 最終ジャッジ日時: 2025-03-28 22:10:37
• 合計ジャッジ時間: 17,018 ms
• ジャッジサーバーID （参考情報）: judge1 / judge2

ファイルパターン	結果
sample	AC * 3
other	AC * 41 WA * 5

ソースコード

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import sys
# sys.setrecursionlimit(200005)
# sys.set_int_max_str_digits(200005)
int1 = lambda x: int(x)-1
pDB = lambda *x: print(*x, end="\n", file=sys.stderr)
p2D = lambda x: print(*x, sep="\n", end="\n\n", file=sys.stderr)
def II(): return int(sys.stdin.readline())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def SI(): return sys.stdin.readline().rstrip()
dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
# inf = -1-(-1 << 31)
inf = -1-(-1 << 62)
# md = 10**9+7
md = 998244353
# Thanks for tatyam
# https://github.com/tatyam-prime/SortedSet/blob/main/SortedSet.py
import math
from bisect import bisect_left, bisect_right
from typing import Generic, Iterable, Iterator, TypeVar, Optional, List
T = TypeVar('T')
class SortedSet(Generic[T]):
    BUCKET_RATIO = 50
    REBUILD_RATIO = 170
    def _build(self, a=None) -> None:
        "Evenly divide `a` into buckets."
        if a is None: a = list(self)
        size = self.size = len(a)
        bucket_size = int(math.ceil(math.sqrt(size/self.BUCKET_RATIO)))
        self.a = [a[size*i//bucket_size: size*(i+1)//bucket_size] for i in range(bucket_size)]
    def __init__(self, a: Iterable[T] = []) -> None:
        "Make a new SortedSet from iterable. / O(N) if sorted and unique / O(N log N)"
        a = list(a)
        if not all(a[i] < a[i+1] for i in range(len(a)-1)):
            a = sorted(set(a))
        self._build(a)
    def __iter__(self) -> Iterator[T]:
        for i in self.a:
            for j in i: yield j
    def __reversed__(self) -> Iterator[T]:
        for i in reversed(self.a):
            for j in reversed(i): yield j
    def __len__(self) -> int:
        return self.size
    def __repr__(self) -> str:
        return "SortedSet"+str(self.a)
    def __str__(self) -> str:
        s = str(list(self))
        return "{"+s[1: len(s)-1]+"}"
    def _find_bucket(self, x: T) -> List[T]:
        "Find the bucket which should contain x. self must not be empty."
        for a in self.a:
            if x <= a[-1]: return a
        return a
    def __contains__(self, x: T) -> bool:
        if self.size == 0: return False
        a = self._find_bucket(x)
        i = bisect_left(a, x)
        return i != len(a) and a[i] == x
    def add(self, x: T) -> bool:
        "Add an element and return True if added. / O(√N)"
        if self.size == 0:
            self.a = [[x]]
            self.size = 1
            return True
        a = self._find_bucket(x)
        i = bisect_left(a, x)
        if i != len(a) and a[i] == x: return False
        a.insert(i, x)
        self.size += 1
        if len(a) > len(self.a)*self.REBUILD_RATIO:
            self._build()
        return True
    def discard(self, x: T) -> bool:
        "Remove an element and return True if removed. / O(√N)"
        if self.size == 0: return False
        a = self._find_bucket(x)
        i = bisect_left(a, x)
        if i == len(a) or a[i] != x: return False
        a.pop(i)
        self.size -= 1
        if len(a) == 0: self._build()
        return True
    def lt(self, x: T) -> Optional[T]:
        "Find the largest element < x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] < x:
                return a[bisect_left(a, x)-1]
    def le(self, x: T) -> Optional[T]:
        "Find the largest element <= x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] <= x:
                return a[bisect_right(a, x)-1]
    def gt(self, x: T) -> Optional[T]:
        "Find the smallest element > x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] > x:
                return a[bisect_right(a, x)]
    def ge(self, x: T) -> Optional[T]:
        "Find the smallest element >= x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] >= x:
                return a[bisect_left(a, x)]
    def __getitem__(self, x: int) -> T:
        "Return the x-th element, or IndexError if it doesn't exist."
        if x < 0: x += self.size
        if x < 0: raise IndexError
        for a in self.a:
            if x < len(a): return a[x]
            x -= len(a)
        raise IndexError
    def index(self, x: T) -> int:
        "Count the number of elements < x."
        ans = 0
        for a in self.a:
            if a[-1] >= x:
                return ans+bisect_left(a, x)
            ans += len(a)
        return ans
    def index_right(self, x: T) -> int:
        "Count the number of elements <= x."
        ans = 0
        for a in self.a:
            if a[-1] > x:
                return ans+bisect_right(a, x)
            ans += len(a)
        return ans
def mex(aa):
    st = set(aa)
    for i in range(len(aa)):
        if i not in st: return i
    return len(aa)
n, x = LI()
aa = LI()
cnt = [0]*(n+1)
for a in aa:
    if a <= n:
        cnt[a] += 1
s = 0
zero = SortedSet()
for a in range(n+1):
    if cnt[a] == 0: zero.add(a)
    if cnt[a] == 1: s += 1
a = zero[0]
zero.discard(a)
aa.append(a)
cnt[a] += 1
s += 1
while s < n:
    a = aa[-n-1]
    if a<=n:
        cnt[a] -= 1
        if cnt[a] == 0:
            s -= 1
            zero.add(a)
        if cnt[a] == 1:
            s += 1
    a = zero[0]
    zero.discard(a)
    aa.append(a)
    cnt[a] += 1
    s += 1
x -= 1
if x >= len(aa):
    d = x-len(aa)+1
    p = (d+n)//(n+1)
    x -= (n+1)*p
print(aa[x])
 
 
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