結果
| 問題 |
No.3097 Azuki Kurai
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2025-03-29 04:52:52 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
RE
|
| 実行時間 | - |
| コード長 | 1,684 bytes |
| コンパイル時間 | 408 ms |
| コンパイル使用メモリ | 82,912 KB |
| 実行使用メモリ | 92,712 KB |
| 最終ジャッジ日時 | 2025-03-29 04:52:59 |
| 合計ジャッジ時間 | 5,272 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| other | RE * 32 |
ソースコード
import sys
input = sys.stdin.read
def chmin(a, b):
return min(a, b)
def main():
data = input().split()
idx = 0
N = int(data[idx])
M = int(data[idx + 1])
K = int(data[idx + 2])
idx += 3
A = list(map(int, data[idx:idx + N]))
idx += N
linf = float('inf')
dp = [[linf] * (1 << N) for _ in range(M + 1)]
for i in range(1 << N):
dp[0][i] = sum(A[j] for j in range(N) if not (i & (1 << j)))
popcount = [bin(i).count('1') for i in range(1 << N)]
pl = [[(popcount[i] - popcount[c]) * K for c in range(i, 0, -1 & i)] + [(popcount[i] - popcount[0]) * K] for i in range(1 << N)]
mae = [[[] for _ in range(1 << N)] for _ in range(N)]
for p in range(N):
for i in range(1 << N):
for c in range(i, 0, -1 & i):
now = i
now |= ((c * 2) - ((c * 2) & (1 << N)))
now |= (((c * 2) & (1 << N)) >> N)
now |= (c // 2)
now |= (c % 2) * (1 << (N - 1))
now -= (now & (1 << p))
mae[p][i].append(now)
now = i
now -= (now & (1 << p))
mae[p][i].append(now)
for p in range(M):
B = int(data[idx]) - 1
idx += 1
for i in range(1 << N):
F = 0
for c in range(i, 0, -1 & i):
dp[p + 1][mae[B][i][F]] = chmin(dp[p + 1][mae[B][i][F]], dp[p][i] + pl[i][F])
F += 1
dp[p + 1][mae[B][i][F]] = chmin(dp[p + 1][mae[B][i][F]], dp[p][i] + pl[i][F])
for i in range(1, M + 1):
print(dp[i][0])
if __name__ == "__main__":
main()