結果
| 問題 |
No.270 next_permutation (1)
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-03-31 17:21:11 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 144 ms / 2,000 ms |
| コード長 | 2,068 bytes |
| コンパイル時間 | 188 ms |
| コンパイル使用メモリ | 82,240 KB |
| 実行使用メモリ | 117,192 KB |
| 最終ジャッジ日時 | 2025-03-31 17:22:23 |
| 合計ジャッジ時間 | 2,490 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 15 |
ソースコード
def main():
import sys
input = sys.stdin.read
data = input().split()
idx = 0
N = int(data[idx])
idx += 1
K = int(data[idx])
idx += 1
if K == 0:
print(0)
return
p = list(map(int, data[idx:idx+N]))
idx += N
B = list(map(int, data[idx:idx+N]))
current = p.copy()
sum_dist = 0
for i in range(N):
sum_dist += abs(current[i] - B[i])
total = sum_dist
remaining = K - 1
while remaining > 0:
# Find the largest i such that current[i] < current[i+1]
i = N - 2
while i >= 0 and current[i] >= current[i+1]:
i -= 1
if i == -1:
# current is the last permutation, wrap around to the first
for j in range(N):
sum_dist -= abs(current[j] - B[j])
current[j] = j + 1
sum_dist += abs(current[j] - B[j])
total += sum_dist
remaining -= 1
continue
# Find the largest j > i such that current[j] > current[i]
j = N - 1
while current[j] <= current[i]:
j -= 1
# Swap current[i] and current[j]
sum_dist -= abs(current[i] - B[i])
sum_dist -= abs(current[j] - B[j])
current[i], current[j] = current[j], current[i]
sum_dist += abs(current[i] - B[i])
sum_dist += abs(current[j] - B[j])
# Reverse current[i+1:]
# Calculate the old contribution and update sum_dist
left = i + 1
right = N - 1
while left < right:
sum_dist -= abs(current[left] - B[left])
sum_dist -= abs(current[right] - B[right])
current[left], current[right] = current[right], current[left]
sum_dist += abs(current[left] - B[left])
sum_dist += abs(current[right] - B[right])
left += 1
right -= 1
total += sum_dist
remaining -= 1
print(total)
if __name__ == "__main__":
main()
lam6er