結果
問題 | No.270 next_permutation (1) |
ユーザー |
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提出日時 | 2025-03-31 17:21:11 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 144 ms / 2,000 ms |
コード長 | 2,068 bytes |
コンパイル時間 | 188 ms |
コンパイル使用メモリ | 82,240 KB |
実行使用メモリ | 117,192 KB |
最終ジャッジ日時 | 2025-03-31 17:22:23 |
合計ジャッジ時間 | 2,490 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
other | AC * 15 |
ソースコード
def main():import sysinput = sys.stdin.readdata = input().split()idx = 0N = int(data[idx])idx += 1K = int(data[idx])idx += 1if K == 0:print(0)returnp = list(map(int, data[idx:idx+N]))idx += NB = list(map(int, data[idx:idx+N]))current = p.copy()sum_dist = 0for i in range(N):sum_dist += abs(current[i] - B[i])total = sum_distremaining = K - 1while remaining > 0:# Find the largest i such that current[i] < current[i+1]i = N - 2while i >= 0 and current[i] >= current[i+1]:i -= 1if i == -1:# current is the last permutation, wrap around to the firstfor j in range(N):sum_dist -= abs(current[j] - B[j])current[j] = j + 1sum_dist += abs(current[j] - B[j])total += sum_distremaining -= 1continue# Find the largest j > i such that current[j] > current[i]j = N - 1while current[j] <= current[i]:j -= 1# Swap current[i] and current[j]sum_dist -= abs(current[i] - B[i])sum_dist -= abs(current[j] - B[j])current[i], current[j] = current[j], current[i]sum_dist += abs(current[i] - B[i])sum_dist += abs(current[j] - B[j])# Reverse current[i+1:]# Calculate the old contribution and update sum_distleft = i + 1right = N - 1while left < right:sum_dist -= abs(current[left] - B[left])sum_dist -= abs(current[right] - B[right])current[left], current[right] = current[right], current[left]sum_dist += abs(current[left] - B[left])sum_dist += abs(current[right] - B[right])left += 1right -= 1total += sum_distremaining -= 1print(total)if __name__ == "__main__":main()