結果
問題 |
No.2219 Re:010
|
ユーザー |
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提出日時 | 2025-03-31 17:32:43 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 64 ms / 2,000 ms |
コード長 | 1,154 bytes |
コンパイル時間 | 185 ms |
コンパイル使用メモリ | 82,388 KB |
実行使用メモリ | 75,976 KB |
最終ジャッジ日時 | 2025-03-31 17:33:39 |
合計ジャッジ時間 | 2,372 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 21 |
ソースコード
MOD = 998244353 s = input().strip() dp0 = 1 # State 0: No part of '010' formed dp1 = 0 # State 1: First '0' formed dp2 = 0 # State 2: '0' followed by '1' formed dp3 = 0 # State 3: '010' fully formed for c in s: if c == '0': # Transition for '0' nd0 = dp0 nd1 = (dp1 + dp0) % MOD nd2 = dp2 nd3 = (dp3 + dp2) % MOD elif c == '1': # Transition for '1' nd0 = dp0 nd1 = dp1 nd2 = (dp2 + dp1) % MOD nd3 = dp3 else: # Transition for '?' considering both '0' and '1' # Case when '?' is treated as '0' nd0_0 = dp0 nd1_0 = (dp1 + dp0) % MOD nd2_0 = dp2 nd3_0 = (dp3 + dp2) % MOD # Case when '?' is treated as '1' nd0_1 = dp0 nd1_1 = dp1 nd2_1 = (dp2 + dp1) % MOD nd3_1 = dp3 # Combine both cases nd0 = (nd0_0 + nd0_1) % MOD nd1 = (nd1_0 + nd1_1) % MOD nd2 = (nd2_0 + nd2_1) % MOD nd3 = (nd3_0 + nd3_1) % MOD # Update states for next iteration dp0, dp1, dp2, dp3 = nd0 % MOD, nd1 % MOD, nd2 % MOD, nd3 % MOD print(dp3 % MOD)