結果
| 問題 | No.2219 Re:010 | 
| コンテスト | |
| ユーザー |  lam6er | 
| 提出日時 | 2025-03-31 17:32:43 | 
| 言語 | PyPy3 (7.3.15) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 64 ms / 2,000 ms | 
| コード長 | 1,154 bytes | 
| コンパイル時間 | 185 ms | 
| コンパイル使用メモリ | 82,388 KB | 
| 実行使用メモリ | 75,976 KB | 
| 最終ジャッジ日時 | 2025-03-31 17:33:39 | 
| 合計ジャッジ時間 | 2,372 ms | 
| ジャッジサーバーID (参考情報) | judge2 / judge5 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 3 | 
| other | AC * 21 | 
ソースコード
MOD = 998244353
s = input().strip()
dp0 = 1  # State 0: No part of '010' formed
dp1 = 0  # State 1: First '0' formed
dp2 = 0  # State 2: '0' followed by '1' formed
dp3 = 0  # State 3: '010' fully formed
for c in s:
    if c == '0':
        # Transition for '0'
        nd0 = dp0
        nd1 = (dp1 + dp0) % MOD
        nd2 = dp2
        nd3 = (dp3 + dp2) % MOD
    elif c == '1':
        # Transition for '1'
        nd0 = dp0
        nd1 = dp1
        nd2 = (dp2 + dp1) % MOD
        nd3 = dp3
    else:
        # Transition for '?' considering both '0' and '1'
        # Case when '?' is treated as '0'
        nd0_0 = dp0
        nd1_0 = (dp1 + dp0) % MOD
        nd2_0 = dp2
        nd3_0 = (dp3 + dp2) % MOD
        # Case when '?' is treated as '1'
        nd0_1 = dp0
        nd1_1 = dp1
        nd2_1 = (dp2 + dp1) % MOD
        nd3_1 = dp3
        # Combine both cases
        nd0 = (nd0_0 + nd0_1) % MOD
        nd1 = (nd1_0 + nd1_1) % MOD
        nd2 = (nd2_0 + nd2_1) % MOD
        nd3 = (nd3_0 + nd3_1) % MOD
    
    # Update states for next iteration
    dp0, dp1, dp2, dp3 = nd0 % MOD, nd1 % MOD, nd2 % MOD, nd3 % MOD
print(dp3 % MOD)
            
            
            
        