結果
問題 | No.484 収穫 |
ユーザー |
![]() |
提出日時 | 2025-03-31 17:34:59 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,018 bytes |
コンパイル時間 | 265 ms |
コンパイル使用メモリ | 82,792 KB |
実行使用メモリ | 425,936 KB |
最終ジャッジ日時 | 2025-03-31 17:36:13 |
合計ジャッジ時間 | 20,236 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 2 WA * 1 |
other | AC * 12 WA * 9 |
ソースコード
n = int(input())A = list(map(int, input().split()))# Convert to 1-based indexA = [0] + AINF = 10**18# dp[l][r][0] represents time when at left end l after covering [l..r]# dp[l][r][1] represents time when at right end r after covering [l..r]dp = [[[INF] * 2 for _ in range(n + 2)] for __ in range(n + 2)]for i in range(1, n + 1):dp[i][i][0] = A[i]dp[i][i][1] = A[i]for length in range(2, n + 1):for l in range(1, n - length + 2):r = l + length - 1# Update dp[l][r][0]: come from [l+1][r] which is left end (l+1)time_candidate = dp[l+1][r][0] + 1new_time = max(time_candidate, A[l])if new_time < dp[l][r][0]:dp[l][r][0] = new_time# Update dp[l][r][1]: come from [l][r-1] which is right end (r-1)time_candidate = dp[l][r-1][1] + 1new_time = max(time_candidate, A[r])if new_time < dp[l][r][1]:dp[l][r][1] = new_timeresult = min(dp[1][n][0], dp[1][n][1])print(result)