結果
| 問題 |
No.1284 Flip Game
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-03-31 17:46:06 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 2,017 bytes |
| コンパイル時間 | 567 ms |
| コンパイル使用メモリ | 82,096 KB |
| 実行使用メモリ | 122,332 KB |
| 最終ジャッジ日時 | 2025-03-31 17:46:34 |
| 合計ジャッジ時間 | 8,795 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 14 WA * 14 |
ソースコード
import heapq
def main():
n = int(input())
c = [list(map(int, input().split())) for _ in range(n)]
heap = []
dist = dict()
# Initialize all possible starting points (step 0)
for start in range(n):
mask_white = 1 << start
mask_b = 0
state = (start, mask_white, mask_b)
heapq.heappush(heap, (0, start, mask_white, mask_b))
dist[state] = 0
while heap:
current_cost, prev_p, mask_white, mask_b = heapq.heappop(heap)
# Check if we have already processed this state with a lower cost
if dist.get((prev_p, mask_white, mask_b), float('inf')) < current_cost:
continue
# Generate all possible next moves by choosing a red card (not in mask_white)
for q in range(n):
if not (mask_white & (1 << q)):
new_cost = current_cost + c[prev_p][q]
new_mask_white_A = mask_white | (1 << q)
# Check if B can flip the previous_p
if (mask_b & (1 << prev_p)) == 0:
new_mask_white_B = new_mask_white_A ^ (1 << prev_p)
new_mask_b = mask_b | (1 << prev_p)
else:
new_mask_white_B = new_mask_white_A
new_mask_b = mask_b
# Check if this new state is the terminal state
if new_mask_white_B == (1 << n) - 1 and new_mask_b == mask_b:
print(new_cost)
return
new_state = (q, new_mask_white_B, new_mask_b)
# Update the distance if this path is better
if new_cost < dist.get(new_state, float('inf')):
dist[new_state] = new_cost
heapq.heappush(heap, (new_cost, q, new_mask_white_B, new_mask_b))
# If not found (which shouldn't happen as per problem statement)
print(-1)
if __name__ == "__main__":
main()
lam6er