結果
| 問題 | No.2122 黄金比で擬似乱数生成 |
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-03-31 17:49:56 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,852 bytes |
| コンパイル時間 | 317 ms |
| コンパイル使用メモリ | 82,416 KB |
| 実行使用メモリ | 71,960 KB |
| 最終ジャッジ日時 | 2025-03-31 17:50:39 |
| 合計ジャッジ時間 | 2,369 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 16 WA * 10 |
ソースコード
def multiply_matrix(a, b, mod):
res = [[0]*2 for _ in range(2)]
res[0][0] = (a[0][0] * b[0][0] + a[0][1] * b[1][0]) % mod
res[0][1] = (a[0][0] * b[0][1] + a[0][1] * b[1][1]) % mod
res[1][0] = (a[1][0] * b[0][0] + a[1][1] * b[1][0]) % mod
res[1][1] = (a[1][0] * b[0][1] + a[1][1] * b[1][1]) % mod
return res
def matrix_power(mat, power, mod):
result = [[1,0], [0,1]] # Identity matrix
while power > 0:
if power % 2 == 1:
result = multiply_matrix(result, mat, mod)
mat = multiply_matrix(mat, mat, mod)
power = power // 2
return result
def compute_new_n(n, M, mod):
if M == 0:
return 0 % mod
mat = [[n, 1], [1, 0]]
power = M - 1
mat_pow = matrix_power(mat, power, mod)
# Multiply with [1, 0] vector
b_m = (mat_pow[0][0] * 1 + mat_pow[0][1] * 0) % mod
return b_m
def main():
S = input().strip()
M = int(input().strip())
L = int(input().strip())
current_n = int(S)
mod = 10000
history = []
found_cycle = False
cycle_start = 0
cycle_length = 0
for _ in range(L):
# Check if current_n is in history to find cycle
if current_n in history:
idx = history.index(current_n)
cycle_start = idx
cycle_length = len(history) - idx
remaining = L - _
total_remaining = remaining
final_pos = idx + (total_remaining) % cycle_length
current_n = history[final_pos]
found_cycle = True
break
history.append(current_n)
# Compute new_n
new_n = compute_new_n(current_n, M, mod)
current_n = new_n
if not found_cycle:
current_n = current_n % mod
# Format the result to 4 digits
print("{:04d}".format(current_n))
if __name__ == "__main__":
main()
lam6er