結果
| 問題 |
No.2005 Sum of Power Sums
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-03-31 17:50:23 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 2,009 bytes |
| コンパイル時間 | 267 ms |
| コンパイル使用メモリ | 83,096 KB |
| 実行使用メモリ | 161,280 KB |
| 最終ジャッジ日時 | 2025-03-31 17:51:13 |
| 合計ジャッジ時間 | 6,029 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 12 TLE * 1 -- * 5 |
ソースコード
mod = 998244353
def main():
import sys
input = sys.stdin.read().split()
idx = 0
N = int(input[idx]); idx += 1
M = int(input[idx]); idx += 1
K = list(map(int, input[idx:idx + N]))
idx += N
max_k = max(K) if K else 0
max_stirling = max_k
max_N = N
# Precompute Stirling numbers of the second kind
stirling = [[0] * (max_stirling + 1) for _ in range(max_stirling + 1)]
stirling[0][0] = 1
for k in range(1, max_stirling + 1):
for m in range(1, k + 1):
stirling[k][m] = (stirling[k-1][m] * m + stirling[k-1][m-1]) % mod
# Precompute factorials and inverse factorials up to max_r = 5000 + 2e5
max_r = max_k + max_N
fac = [1] * (max_r + 1)
for i in range(1, max_r + 1):
fac[i] = fac[i-1] * i % mod
inv_fac = [1] * (max_r + 1)
inv_fac[max_r] = pow(fac[max_r], mod-2, mod)
for i in range(max_r-1, -1, -1):
inv_fac[i] = inv_fac[i+1] * (i+1) % mod
# Compute rem = (M + N) mod mod
rem = (M % mod + N % mod) % mod
# Precompute perm[r] = product_{i=0}^{r-1} (rem - i) mod mod for 0 <= r <= max_r
max_perm_r = max_k + max_N
perm = [1] * (max_perm_r + 1)
for r in range(1, max_perm_r + 1):
term = (rem - (r-1)) % mod
perm[r] = perm[r-1] * term % mod
# Compute the answer
answer = 0
for k in K:
current_sum = 0
for m in range(0, k+1):
s = stirling[k][m]
if s == 0:
continue
r = m + N
if r > max_perm_r:
c = 0
else:
numerator = perm[r]
denom = inv_fac[r]
c = numerator * denom % mod
if r > rem:
c = 0
term = s * fac[m] % mod
term = term * c % mod
current_sum = (current_sum + term) % mod
answer = (answer + current_sum) % mod
print(answer % mod)
if __name__ == '__main__':
main()
lam6er