結果
問題 |
No.2005 Sum of Power Sums
|
ユーザー |
![]() |
提出日時 | 2025-03-31 17:50:23 |
言語 | PyPy3 (7.3.15) |
結果 |
TLE
|
実行時間 | - |
コード長 | 2,009 bytes |
コンパイル時間 | 267 ms |
コンパイル使用メモリ | 83,096 KB |
実行使用メモリ | 161,280 KB |
最終ジャッジ日時 | 2025-03-31 17:51:13 |
合計ジャッジ時間 | 6,029 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 12 TLE * 1 -- * 5 |
ソースコード
mod = 998244353 def main(): import sys input = sys.stdin.read().split() idx = 0 N = int(input[idx]); idx += 1 M = int(input[idx]); idx += 1 K = list(map(int, input[idx:idx + N])) idx += N max_k = max(K) if K else 0 max_stirling = max_k max_N = N # Precompute Stirling numbers of the second kind stirling = [[0] * (max_stirling + 1) for _ in range(max_stirling + 1)] stirling[0][0] = 1 for k in range(1, max_stirling + 1): for m in range(1, k + 1): stirling[k][m] = (stirling[k-1][m] * m + stirling[k-1][m-1]) % mod # Precompute factorials and inverse factorials up to max_r = 5000 + 2e5 max_r = max_k + max_N fac = [1] * (max_r + 1) for i in range(1, max_r + 1): fac[i] = fac[i-1] * i % mod inv_fac = [1] * (max_r + 1) inv_fac[max_r] = pow(fac[max_r], mod-2, mod) for i in range(max_r-1, -1, -1): inv_fac[i] = inv_fac[i+1] * (i+1) % mod # Compute rem = (M + N) mod mod rem = (M % mod + N % mod) % mod # Precompute perm[r] = product_{i=0}^{r-1} (rem - i) mod mod for 0 <= r <= max_r max_perm_r = max_k + max_N perm = [1] * (max_perm_r + 1) for r in range(1, max_perm_r + 1): term = (rem - (r-1)) % mod perm[r] = perm[r-1] * term % mod # Compute the answer answer = 0 for k in K: current_sum = 0 for m in range(0, k+1): s = stirling[k][m] if s == 0: continue r = m + N if r > max_perm_r: c = 0 else: numerator = perm[r] denom = inv_fac[r] c = numerator * denom % mod if r > rem: c = 0 term = s * fac[m] % mod term = term * c % mod current_sum = (current_sum + term) % mod answer = (answer + current_sum) % mod print(answer % mod) if __name__ == '__main__': main()