結果
問題 |
No.2423 Merge Stones
|
ユーザー |
![]() |
提出日時 | 2025-03-31 17:51:11 |
言語 | PyPy3 (7.3.15) |
結果 |
TLE
|
実行時間 | - |
コード長 | 2,576 bytes |
コンパイル時間 | 265 ms |
コンパイル使用メモリ | 82,760 KB |
実行使用メモリ | 67,120 KB |
最終ジャッジ日時 | 2025-03-31 17:52:14 |
合計ジャッジ時間 | 7,014 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 10 TLE * 1 -- * 61 |
ソースコード
def main(): import sys input = sys.stdin.read().split() idx = 0 N = int(input[idx]) idx += 1 K = int(input[idx]) idx += 1 A = list(map(int, input[idx:idx+N])) idx += N C = list(map(int, input[idx:idx+N])) idx += N if N == 1: print(A[0]) return duplicated_A = A * 2 duplicated_C = C * 2 max_color = 50 # Precompute prefix sums prefix_sum = [0] * (2 * N + 1) for i in range(2 * N): prefix_sum[i+1] = prefix_sum[i] + duplicated_A[i] # Precompute allowed masks for each color allowed_masks = [0] * (max_color + 1) # 1-based for c in range(1, max_color + 1): low = max(1, c - K) high = min(max_color, c + K) mask = 0 for neighbor in range(low, high + 1): mask |= 1 << (neighbor - 1) # neighbor is 1-based, stored as bit (neighbor-1) allowed_masks[c] = mask # Initialize DP table DP = [[0] * (2 * N) for _ in range(2 * N)] for i in range(2 * N): color = duplicated_C[i] DP[i][i] = 1 << (color - 1) # color 1 is bit 0 max_sum = max(A) for length in range(2, N + 1): for i in range(2 * N - length + 1): j = i + length - 1 current_mask = 0 for k in range(i, j): left_mask = DP[i][k] right_mask = DP[k+1][j] left_compatible = 0 for c in range(1, max_color + 1): if (left_mask & (1 << (c-1))) == 0: continue if (allowed_masks[c] & right_mask) != 0: left_compatible |= (1 << (c-1)) right_compatible = 0 for c in range(1, max_color + 1): if (right_mask & (1 << (c-1))) == 0: continue if (allowed_masks[c] & left_mask) != 0: right_compatible |= (1 << (c-1)) merged = left_compatible | right_compatible current_mask |= merged DP[i][j] = current_mask if current_mask != 0: current_sum = prefix_sum[j + 1] - prefix_sum[i] if current_sum > max_sum: max_sum = current_sum # Check for all possible intervals in the original circular arrangement by considering all starts # Also check all lengths up to N print(max_sum) if __name__ == '__main__': main()