結果
| 問題 | 
                            No.8119 間に合いませんでした><;
                             | 
                    
| コンテスト | |
| ユーザー | 
                             iomir
                         | 
                    
| 提出日時 | 2025-04-01 23:00:05 | 
| 言語 | C++23  (gcc 13.3.0 + boost 1.87.0)  | 
                    
| 結果 | 
                             
                                TLE
                                 
                             
                            
                         | 
                    
| 実行時間 | - | 
| コード長 | 2,936 bytes | 
| コンパイル時間 | 3,509 ms | 
| コンパイル使用メモリ | 278,988 KB | 
| 実行使用メモリ | 14,904 KB | 
| 最終ジャッジ日時 | 2025-04-01 23:00:11 | 
| 合計ジャッジ時間 | 5,840 ms | 
| 
                            ジャッジサーバーID (参考情報)  | 
                        judge2 / judge1 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 1 | 
| other | AC * 22 TLE * 1 -- * 6 | 
ソースコード
#include<bits/stdc++.h>
//#include <atcoder/all>
using namespace std;
//using namespace atcoder;
#define all(v) v.begin(),v.end()
using ll = long long;
using ull = unsigned long long;
using lll = __int128;
using vll=vector<ll>;
using vvll = vector<vector<ll>>;
using P = pair<ll,ll>;
using vp=vector<pair<ll, ll>>;
//using mint=modint1000000007;
//using mint=modint998244353;
const ll INF=1ll<<60;
ll mod10=1e9+7;
ll mod99=998244353;
const double PI = acos(-1);
#define rep(i,n) for (ll i=0;i<n;++i)
#define per(i,n) for(ll i=n-1;i>=0;--i)
#define rep2(i,a,n) for (ll i=a;i<n;++i)
#define per2(i,a,n) for (ll i=a;i>=n;--i)
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }
template <long long MOD>
struct modint {
	long long value;
	modint(long long x = 0) {
		if (x >= 0) {
			value = x % MOD;
		} else {
			value = MOD - (-x) % MOD;
		}
	}
	modint operator-() const {
		return modint(-value);
	}
	modint operator+() const {
		return modint(*this);
	}
	modint &operator+=(const modint &other) {
		value += other.value;
		if (value >= MOD) {
			value -= MOD;
		}
		return *this;
	}
	modint &operator-=(const modint &other) {
		value += MOD - other.value;
		if (value >= MOD) {
			value -= MOD;
		}
		return *this;
	}
	modint &operator*=(const modint other) {
		value = value * other.value % MOD;
		return *this;
	}
	modint &operator/=(modint other) {
		(*this) *= other.inv();
		return *this;
	}
	modint operator+(const modint &other) const {
		return modint(*this) += other;
	}
	modint operator-(const modint &other) const {
		return modint(*this) -= other;
	}
	modint operator*(const modint &other) const {
		return modint(*this) *= other;
	}
	modint operator/(const modint &other) const {
		return modint(*this) /= other;
	}
	modint pow(long long x) const {
		modint ret(1), mul(value);
		while (x > 0) {
			if (x % 2 == 1) {
				ret *= mul;
			}
			mul *= mul;
			x /= 2;
		}
		return ret;
	}
	modint inv() const {
		return pow(MOD - 2);
	}
	bool operator==(const modint &other) const {
		return value == other.value;
	}
	bool operator!=(const modint &other) const {
		return value != other.value;
	}
	friend std::ostream &operator<<(std::ostream &os, const modint &x) {
		return os << x.value;
	}
	friend std::istream &operator>>(std::istream &is, modint &x) {
		long long v;
		is >> v;
		x = modint<MOD>(v);
		return is;
	}
};
using mint = modint<998244353>;
using mod107 = modint<1000000007>;
bool solve(){
	ll N;cin>>N;
	string S;cin>>S;
	vector<mint> dp(N+1);
	dp[0]=1;
	vll p={2,10,5};
	rep(i,N){
		ll j=1;
		while(i+j*10<=N){
			bool ok=1;
			for(auto x:p) if(S[i+j*x]=='x') ok=0;
			if(ok) dp[i+j*10]+=dp[i];
		
			j++;
			
		}
	}
	cout << dp[N] << endl;
	return 0;
}
	
int main(){
   cin.tie(0);
   ios::sync_with_stdio(false);
   ll T=1;//cin>>T;
   rep(i,T) solve();
}
	
            
            
            
        
            
iomir