結果
| 問題 | No.3088 XOR = SUM | 
| コンテスト | |
| ユーザー | 👑 | 
| 提出日時 | 2025-04-05 09:08:22 | 
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) | 
| 結果 | 
                                WA
                                 
                             | 
| 実行時間 | - | 
| コード長 | 2,706 bytes | 
| コンパイル時間 | 5,069 ms | 
| コンパイル使用メモリ | 251,212 KB | 
| 実行使用メモリ | 7,720 KB | 
| 最終ジャッジ日時 | 2025-04-05 09:08:45 | 
| 合計ジャッジ時間 | 21,589 ms | 
| ジャッジサーバーID (参考情報) | judge2 / judge4 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 1 | 
| other | AC * 1 WA * 21 | 
ソースコード
#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef pair<int, int> P;
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
int solve(){
	long long n;
	cin >> n;
	if(n == 0){
		cout << "0 0\n";
		return 0;
	}
	
	int MAX = -1;
	for(int j = 60; j >= 0; j--){
		if((n >> j) & 1){
			MAX = j;
			break;
		}
	}
	if(MAX >= 2){
		if(((n >> MAX) & 1 == 1) and ((n >> (MAX - 1)) & 1 == 0) and ((n >>  (MAX - 2)) & 1 != 0)){
			n = (1LL << MAX) - 1;
		}
	}
	
	vector<long long> x(2);
	for(int j = 60; j >= 0; j--){
		if((n >> j) & 1){
			x[0] += (1LL << j);
			if(x[1] == 0LL) swap(x[0], x[1]);
		}
	}
	cout << x[0] << ' ' << x[1] << "\n";
	return 0;
}
int main(){
	int t;
	cin >> t;
	rep(_, t) solve();
	return 0;
}
            
            
            
        