結果
問題 | No.3088 XOR = SUM |
ユーザー |
👑 |
提出日時 | 2025-04-05 09:08:22 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,706 bytes |
コンパイル時間 | 5,069 ms |
コンパイル使用メモリ | 251,212 KB |
実行使用メモリ | 7,720 KB |
最終ジャッジ日時 | 2025-04-05 09:08:45 |
合計ジャッジ時間 | 21,589 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 1 WA * 21 |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,n) for(int i=0;i<n;i++) using namespace std; using namespace atcoder; typedef long long ll; typedef pair<int, int> P; template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;} template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;} template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;} template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;} template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename T> void chmin(T& a, T b){a = min(a, b);} template<typename T> void chmax(T& a, T b){a = max(a, b);} int solve(){ long long n; cin >> n; if(n == 0){ cout << "0 0\n"; return 0; } int MAX = -1; for(int j = 60; j >= 0; j--){ if((n >> j) & 1){ MAX = j; break; } } if(MAX >= 2){ if(((n >> MAX) & 1 == 1) and ((n >> (MAX - 1)) & 1 == 0) and ((n >> (MAX - 2)) & 1 != 0)){ n = (1LL << MAX) - 1; } } vector<long long> x(2); for(int j = 60; j >= 0; j--){ if((n >> j) & 1){ x[0] += (1LL << j); if(x[1] == 0LL) swap(x[0], x[1]); } } cout << x[0] << ' ' << x[1] << "\n"; return 0; } int main(){ int t; cin >> t; rep(_, t) solve(); return 0; }