結果
| 問題 | 
                            No.3110 Like CPCTF?
                             | 
                    
| コンテスト | |
| ユーザー | 
                             | 
                    
| 提出日時 | 2025-04-05 11:21:01 | 
| 言語 | C++23  (gcc 13.3.0 + boost 1.87.0)  | 
                    
| 結果 | 
                             
                                AC
                                 
                             
                            
                         | 
                    
| 実行時間 | 2 ms / 2,000 ms | 
| コード長 | 1,785 bytes | 
| コンパイル時間 | 3,570 ms | 
| コンパイル使用メモリ | 286,112 KB | 
| 実行使用メモリ | 7,844 KB | 
| 最終ジャッジ日時 | 2025-04-18 19:30:33 | 
| 合計ジャッジ時間 | 3,745 ms | 
| 
                            ジャッジサーバーID (参考情報)  | 
                        judge1 / judge3 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 3 | 
| other | AC * 16 | 
ソースコード
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
int n;
string s;
int main(){
    cin >> n >> s;
    vector<vector<int>> suff(n+1, vector<int>(26, 0));
    for (int x = 0; x < 26; x++){
        suff[n][x] = 0;
    }
    for (int i = n-1; i >= 0; i--){
        for (int x = 0; x < 26; x++){
            suff[i][x] = suff[i+1][x];
        }
        suff[i][s[i]-'A']++;
    }
    
    vector<vector<ll>> dp(n+1, vector<ll>(26*26, 0LL));
    for (int a = 0; a < 26; a++){
        for (int b = 0; b < 26; b++){
            dp[n][a*26 + b] = 0;
        }
    }
    for (int i = n-1; i >= 0; i--){
        int l = s[i] - 'A';
        int after = n - (i+1);
        for (int a = 0; a < 26; a++){
            for (int b = 0; b < 26; b++){
                int idx = a * 26 + b;
                ll extra = 0;
                if(a != b && l != a && l != b){
                    int sum = after - suff[i+1][a] - suff[i+1][b];
                    extra = sum - suff[i+1][l];
                }
                dp[i][idx] = dp[i+1][idx] + extra;
            }
        }
    }
    vector<vector<vector<ll>>> pre(26, vector<vector<ll>>(26, vector<ll>(n+1, 0LL)));
    vector<int> cnt(26, 0);
    for (int i = 0; i < n; i++){
        for (int a = 0; a < 26; a++){
            for (int b = 0; b < 26; b++){
                pre[a][b][i+1] = pre[a][b][i];
            }
        }
        int ch = s[i] - 'A';
        for (int a = 0; a < 26; a++){
            pre[a][ch][i+1] += cnt[a];
        }
        cnt[ch]++;
    }
    
    ll ans = 0;
    for (int i3 = 2; i3 <= n-3; i3++){
        int a = s[i3] - 'A';
        for (int b = 0; b < 26; b++){
            if(b == a) continue;
            ans += dp[i3+1][a * 26 + b] * pre[a][b][i3];
        }
    }
    
    cout << ans << "\n";
}