結果
| 問題 |
No.3096 Snake Path
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2025-04-08 19:23:43 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 31 ms / 2,000 ms |
| コード長 | 5,618 bytes |
| コンパイル時間 | 2,897 ms |
| コンパイル使用メモリ | 214,764 KB |
| 実行使用メモリ | 7,848 KB |
| 最終ジャッジ日時 | 2025-04-08 19:23:48 |
| 合計ジャッジ時間 | 4,487 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 35 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
long long mod = 998244353;
//入力が必ず-mod<a<modの時.
struct mint{
long long v = 0;
mint(){} mint(int a){v = a<0?a+mod:a;} mint(long long a){v = a<0?a+mod:a;}
mint(unsigned long long a){v = a;}
long long val(){return v;}
mint &operator=(const mint &b) = default;
mint operator-() const {return mint(0)-(*this);}
mint operator+(const mint b){return mint(v)+=b;}
mint operator-(const mint b){return mint(v)-=b;}
mint operator*(const mint b){return mint(v)*=b;}
mint operator/(const mint b){return mint(v)/=b;}
mint operator+=(const mint b){
v += b.v; if(v >= mod) v -= mod;
return *this;
}
mint operator-=(const mint b){
v -= b.v; if(v < 0) v += mod;
return *this;
}
mint operator*=(const mint b){v = v*b.v%mod; return *this;}
mint operator/=(mint b){
if(b == 0) assert(false);
int left = mod-2;
while(left){if(left&1) *this *= b; b *= b; left >>= 1;}
return *this;
}
mint operator++(){*this += 1; return *this;}
mint operator--(){*this -= 1; return *this;}
mint operator++(int){*this += 1; return *this;}
mint operator--(int){*this -= 1; return *this;}
bool operator==(const mint b){return v == b.v;}
bool operator!=(const mint b){return v != b.v;}
bool operator>(const mint b){return v > b.v;}
bool operator>=(const mint b){return v >= b.v;}
bool operator<(const mint b){return v < b.v;}
bool operator<=(const mint b){return v <= b.v;}
mint pow(long long n){
mint ret = 1,p = v;
if(n < 0) p = p.inv(),n = -n;
while(n){
if(n&1) ret *= p;
p *= p; n >>= 1;
}
return ret;
}
mint inv(){return mint(1)/v;}
};
void jury(int N){
vector<vector<bool>> G(3*N,vector<bool>(3*N));
for(int i=0; i<N; i++){
G.at(i*3).at(i*3+1) = true;
G.at(i*3+1).at(i*3+2) = true;
G.at(i*3+1).at(i*3) = true;
G.at(i*3+2).at(i*3+1) = true;
if(i < N-1){
G.at(i*3+2).at(i*3+3) = true,G.at(i*3+3).at(i*3+2) = true;
}
}
vector<int> P(3*N);
iota(P.begin(),P.end(),0);
vector<int> J(2*N);
long long c = 0;
do{
if(P.at(0) != 0) break;
int edge = 0,pos = 0;
for(int i=0; ; i++){
int one = P.at(i),two = P.at(i+1);
if(G.at(one).at(two) == false){
edge++;
if(abs(one/3-two/3) != 1 || (one+two)%6 != 5){pos = i+2; edge = -1000; break;}
}
if(two == 3*N-1){pos = i+2; break;}
}
c++;
if(edge >= 0) J.at(edge)++;
sort(P.begin()+pos,P.end());
reverse(P.begin()+pos,P.end());
}while(next_permutation(P.begin(),P.end()));
for(int i=1; i<2*N; i++) J.at(i) += J.at(i-1);
for(auto v : J) cout << v << " "; cout << endl;
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int N,K; cin >> N >> K;
if(K == 0){cout << 1 << endl; return 0;}
//jury(N);
vector<mint> dp1(K+1),dp2(K+1),dp3(K+1);
vector<mint> back1(K+1),back3(K+1);
vector<mint> hold1(K+1),hold3(K+1);
dp1.at(K) = 1;
for(int i=0; i<N-1; i++){
vector<mint> next1(K+1),next2(K+1),next3(K+1);
mint add = 0;
if(i%2 == 0){
for(int k=0; k<=K; k++){
dp1.at(k) += back1.at(k);
if(k) dp3.at(k-1) += back3.at(k);
add += back1.at(k);
if(k) add += back3.at(k);
}
}
else{
for(int k=0; k<=K; k++){
if(k) dp1.at(k-1) += back1.at(k);
dp3.at(k) += back3.at(k);
add += back3.at(k);
if(k) add += back1.at(k);
}
}
//cout << i+1 << " " << add << endl;
if(i > 0){
for(int k=0; k<=K; k++){
if(k+2 <= K) back1.at(k) = back1.at(k+2);
if(k+2 <= K) back3.at(k) = back3.at(k+2);
back1.at(k) += hold1.at(k);
back3.at(k) += hold3.at(k);
hold1.at(k) = 0,hold3.at(k) = 0;
}
}
if(i%2 == 0){
for(int k=0; k<=K; k++){
mint sum = dp1.at(k)+dp2.at(k)+dp3.at(k);
if(k) next1.at(k-1) += sum,next2.at(k-1) += sum;
next3.at(k) += sum;
if(k-2 >= 0) hold1.at(k-2) += dp3.at(k),hold3.at(k-2) += dp1.at(k);
}
}
else{
for(int k=0; k<=K; k++){
mint sum = dp1.at(k)+dp2.at(k)+dp3.at(k);
next1.at(k) += sum;
if(k) next2.at(k-1) += sum,next3.at(k-1) += sum;
if(k-2 >= 0) hold1.at(k-2) += dp3.at(k),hold3.at(k-2) += dp1.at(k);
}
}
dp1 = next1,dp2 = next2,dp3 = next3;
}
mint answer = 0;
for(auto v : dp1) answer += v;
for(auto v : dp2) answer += v;
for(auto v : dp3) answer += v;
mint add = answer;
if(N%2){
for(auto v : back1) answer += v;
for(auto v : hold3) answer += v;
back3.at(0) = 0;
for(auto v : back3) answer += v;
back3.at(1) = 0;
for(auto v : back3) answer += v;
}
else{
for(auto v : back3) answer += v;
for(auto v : hold1) answer += v;
back1.at(0) = 0;
for(auto v : back1) answer += v;
back1.at(1) = 0;
for(auto v : back1) answer += v;
}
//cout << N << " " << answer-add << endl;
cout << answer.v << endl;
}