結果
| 問題 |
No.515 典型LCP
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-04-15 20:54:50 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 1,777 bytes |
| コンパイル時間 | 343 ms |
| コンパイル使用メモリ | 81,968 KB |
| 実行使用メモリ | 142,840 KB |
| 最終ジャッジ日時 | 2025-04-15 20:57:08 |
| 合計ジャッジ時間 | 4,979 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 6 TLE * 9 |
ソースコード
import sys
def main():
input = sys.stdin.read().split()
ptr = 0
N = int(input[ptr])
ptr += 1
strings = []
for _ in range(N):
s = input[ptr].strip()
strings.append(s)
ptr += 1
M = int(input[ptr])
x = int(input[ptr+1])
d = int(input[ptr+2])
ptr += 3
mod1 = 10**18 + 3
base1 = 911382629
mod2 = 10**18 + 7
base2 = 3571428571
prefix_hash1 = []
prefix_hash2 = []
lens = []
for s in strings:
n = len(s)
lens.append(n)
h1 = [0] * (n + 1)
h2 = [0] * (n + 1)
for i in range(n):
c = ord(s[i]) - ord('a') + 1
h1[i+1] = (h1[i] * base1 + c) % mod1
h2[i+1] = (h2[i] * base2 + c) % mod2
prefix_hash1.append(h1)
prefix_hash2.append(h2)
n = N
max_x = n * (n - 1)
total = 0
for _ in range(M):
# Generate i and j
div = (n - 1)
xi = x // div
xj = x % div
i_val = xi + 1
j_val = xj + 1
if i_val > j_val:
i_val, j_val = j_val, i_val
else:
j_val += 1
a = i_val - 1
b = j_val - 1
len_a = lens[a]
len_b = lens[b]
min_len = min(len_a, len_b)
low = 0
high = min_len
ans = 0
h1_a = prefix_hash1[a]
h1_b = prefix_hash1[b]
h2_a = prefix_hash2[a]
h2_b = prefix_hash2[b]
while low <= high:
mid = (low + high) // 2
if h1_a[mid] == h1_b[mid] and h2_a[mid] == h2_b[mid]:
ans = mid
low = mid + 1
else:
high = mid - 1
total += ans
x = (x + d) % max_x
print(total)
if __name__ == "__main__":
main()
lam6er