結果
| 問題 |
No.260 世界のなんとか3
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-04-15 21:23:13 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
MLE
|
| 実行時間 | - |
| コード長 | 2,203 bytes |
| コンパイル時間 | 463 ms |
| コンパイル使用メモリ | 82,136 KB |
| 実行使用メモリ | 88,576 KB |
| 最終ジャッジ日時 | 2025-04-15 21:29:28 |
| 合計ジャッジ時間 | 6,969 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 MLE * 2 |
| other | AC * 1 TLE * 2 MLE * 24 |
ソースコード
MOD = 10**9 + 7
def subtract_one(s):
s_list = list(s)
i = len(s_list) - 1
while i >= 0 and s_list[i] == '0':
s_list[i] = '9'
i -= 1
if i == -1:
return '0' # This case should not occur as per problem constraints
s_list[i] = str(int(s_list[i]) - 1)
result = ''.join(s_list).lstrip('0')
return result if result else '0'
def count(x_str):
digits = list(map(int, x_str))
n = len(digits)
from collections import defaultdict
current_dp = defaultdict(int)
current_dp[(True, 0, False, 0, False)] = 1
for i in range(n):
next_dp = defaultdict(int)
for state in current_dp:
tight, mod3, has_three, mod8, started = state
cnt = current_dp[state]
max_d = digits[i] if tight else 9
for d in range(0, max_d + 1):
new_tight = tight and (d == max_d)
new_started = started or (d != 0)
if not started and d == 0:
new_mod3 = 0
new_has_three = False
new_mod8 = 0
new_started_flag = False
else:
if not started:
new_mod3 = d % 3
new_has_three = (d == 3)
new_mod8 = d % 8
new_started_flag = True
else:
new_mod3 = (mod3 + d) % 3
new_has_three = has_three or (d == 3)
new_mod8 = (mod8 * 10 + d) % 8
new_started_flag = True
new_state = (new_tight, new_mod3, new_has_three, new_mod8, new_started_flag)
next_dp[new_state] = (next_dp[new_state] + cnt) % MOD
current_dp = next_dp
total = 0
for state in current_dp:
tight, mod3, has_three, mod8, started = state
if not started:
continue
aho = (mod3 == 0) or has_three
if aho and (mod8 != 0):
total = (total + current_dp[state]) % MOD
return total
A, B = input().split()
A_minus_1 = subtract_one(A)
result = (count(B) - count(A_minus_1)) % MOD
print(result)
lam6er