結果
| 問題 |
No.1428 PeRmutation Question
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-04-15 22:53:39 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 89 ms / 2,000 ms |
| コード長 | 1,884 bytes |
| コンパイル時間 | 286 ms |
| コンパイル使用メモリ | 81,904 KB |
| 実行使用メモリ | 93,212 KB |
| 最終ジャッジ日時 | 2025-04-15 22:55:33 |
| 合計ジャッジ時間 | 3,683 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 30 |
ソースコード
MOD = 10**9 + 7
def main():
import sys
sys.setrecursionlimit(1 << 25)
N = int(sys.stdin.readline())
P = list(map(int, sys.stdin.readline().split()))
P = [p - 1 for p in P] # 0-based index
# Precompute factorial and inverse factorial modulo MOD
max_n = 10**5 + 10
fact = [1] * (max_n)
for i in range(1, max_n):
fact[i] = fact[i-1] * i % MOD
inv_fact = [1] * (max_n)
inv_fact[max_n-1] = pow(fact[max_n-1], MOD-2, MOD)
for i in range(max_n-2, -1, -1):
inv_fact[i] = inv_fact[i+1] * (i+1) % MOD
# Find cycles in P
visited = [False] * N
cycles = []
for i in range(N):
if not visited[i]:
current = i
cycle = []
while not visited[current]:
visited[current] = True
cycle.append(current)
current = P[current]
cycles.append(len(cycle))
# Check if all cycles are odd and each cycle length occurs exactly once
from collections import defaultdict
cycle_counts = defaultdict(int)
for c in cycles:
cycle_counts[c] += 1
all_odd = all(c % 2 == 1 for c in cycles)
all_distinct = all(cnt == 1 for cnt in cycle_counts.values())
# Compute denominator
denominator = 1
for c in cycle_counts:
m = cycle_counts[c]
denominator = denominator * pow(c, m, MOD) % MOD
denominator = denominator * fact[m] % MOD
# Compute conjugacy class size
if N == 0:
conj_size = 0
else:
conj_size = fact[N] * pow(denominator, MOD-2, MOD) % MOD
# Determine answer
if all_odd and all_distinct:
if N == 1:
print(1 % MOD)
else:
inv2 = pow(2, MOD-2, MOD)
ans = conj_size * inv2 % MOD
print(ans)
else:
print(conj_size % MOD)
if __name__ == '__main__':
main()
lam6er