結果

問題 No.260 世界のなんとか3
ユーザー parukiparuki
提出日時 2016-07-25 18:32:49
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 40 ms / 2,000 ms
コード長 3,240 bytes
コンパイル時間 1,754 ms
コンパイル使用メモリ 167,220 KB
実行使用メモリ 7,552 KB
最終ジャッジ日時 2024-04-25 07:52:27
合計ジャッジ時間 3,318 ms
ジャッジサーバーID
(参考情報)
judge1 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 4 ms
7,296 KB
testcase_01 AC 4 ms
7,296 KB
testcase_02 AC 5 ms
7,296 KB
testcase_03 AC 40 ms
7,424 KB
testcase_04 AC 39 ms
7,424 KB
testcase_05 AC 11 ms
7,424 KB
testcase_06 AC 9 ms
7,296 KB
testcase_07 AC 28 ms
7,424 KB
testcase_08 AC 21 ms
7,424 KB
testcase_09 AC 14 ms
7,424 KB
testcase_10 AC 31 ms
7,424 KB
testcase_11 AC 29 ms
7,424 KB
testcase_12 AC 20 ms
7,424 KB
testcase_13 AC 9 ms
7,424 KB
testcase_14 AC 27 ms
7,424 KB
testcase_15 AC 10 ms
7,424 KB
testcase_16 AC 24 ms
7,552 KB
testcase_17 AC 20 ms
7,424 KB
testcase_18 AC 19 ms
7,424 KB
testcase_19 AC 24 ms
7,424 KB
testcase_20 AC 18 ms
7,552 KB
testcase_21 AC 16 ms
7,424 KB
testcase_22 AC 27 ms
7,424 KB
testcase_23 AC 6 ms
7,424 KB
testcase_24 AC 22 ms
7,424 KB
testcase_25 AC 21 ms
7,424 KB
testcase_26 AC 22 ms
7,424 KB
testcase_27 AC 4 ms
7,296 KB
testcase_28 AC 39 ms
7,424 KB
testcase_29 AC 38 ms
7,296 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include "bits/stdc++.h"
using namespace std;
#define FOR(i,j,k) for(int (i)=(j);(i)<(int)(k);++(i))
#define rep(i,j) FOR(i,0,j)
#define each(x,y) for(auto &(x):(y))
#define mp make_pair
#define all(x) (x).begin(),(x).end()
#define debug(x) cout<<#x<<": "<<(x)<<endl
#define smax(x,y) (x)=max((x),(y))
#define smin(x,y) (x)=min((x),(y))
#define MEM(x,y) memset((x),(y),sizeof (x))
#define sz(x) (int)(x).size()
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<ll> vll;

template<int MOD>
class ModInt{
public:
    ModInt():value(0){}
    ModInt(long long val):value((int)(val<0?MOD+val%MOD:val%MOD)){ }

    ModInt& operator+=(ModInt that){
        value = value+that.value;
        if(value>=MOD)value-=MOD;
        return *this;
    }
    ModInt& operator-=(ModInt that){
        value -= that.value;
        if(value<0)value+=MOD;
        return *this;
    }
    ModInt& operator*=(ModInt that){
        value = (int)((long long)value * that.value % MOD);
        return *this;
    }
    ModInt &operator/=(ModInt that){
        return *this *= that.inverse();
    }
    ModInt operator+(ModInt that) const{
        return ModInt(*this)+=that;
    }
    ModInt operator-(ModInt that) const{
        return ModInt(*this)-=that;
    }
    ModInt operator*(ModInt that) const{
        return ModInt(*this)*=that;
    }
    ModInt operator/(ModInt that) const {
        return ModInt(*this) /= that;
    }
    ModInt operator^(long long k) const{
        if(value == 0)return 0;
        ModInt n = *this, res = 1;
        while(k){
            if(k & 1)res *= n;
            n *= n;
            k >>= 1;
        }
        return res;
    }
    ModInt inverse() const {
        long long a = value, b = MOD, u = 1, v = 0;
        while(b) {
            long long t = a / b;
            a -= t * b;
            swap(a, b);
            u -= t * v;
            swap(u, v);
        }
        return ModInt(u);
    }
    int toi() const{ return value; }

private:
    int value;
};
typedef ModInt<1000000007> mint;
ostream& operator<<(ostream& os, const mint& x){
    os << x.toi();
    return os;
}

string nstr(){
    static const int MAX_LEN = 100001;
    static char res_[MAX_LEN];
    scanf("%s",res_);
    return string(res_);
}

mint dp[10010][24][2][2];

string A, B;

mint f(string s){
    rep(i, sz(s) + 1)rep(j, 24)rep(k, 2)rep(l, 2)dp[i][j][k][l] = 0;
    dp[0][0][0][0] = 1;
    rep(i, sz(s))rep(md24, 24)rep(d3, 2)rep(les, 2){
        mint val = dp[i][md24][d3][les];
        if(val.toi() == 0)continue;
        rep(d, 10){
            int nMd24 = (md24 * 10 + d)%24, nD3 = d3|(d==3), nLes = les|(d<s[i]);
            if(!les && d > s[i])break;
            dp[i + 1][nMd24][nD3][nLes] += val;
        }
    }
    mint res = 0;
    rep(md24, 24)rep(d3, 2)rep(les, 2){
        mint val = dp[sz(s)][md24][d3][les];
        if((d3 || md24 % 3 == 0) && md24 % 8)res += val;
    }
    return res;
}

int main(){
    A = nstr();
    B = nstr();
    each(a, A)a -= '0';
    each(b, B)b -= '0';

    for(int i = sz(A) - 1; i >= 0; i--){
        if(A[i] == 0)A[i] = 9;
        else{
            A[i]--;
            break;
        }
    }

    mint ans = f(B);
    ans -= f(A);
    cout << ans << endl;
}
0