結果
| 問題 |
No.1513 simple 門松列 problem
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-04-16 00:22:17 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 713 ms / 3,000 ms |
| コード長 | 3,317 bytes |
| コンパイル時間 | 365 ms |
| コンパイル使用メモリ | 81,860 KB |
| 実行使用メモリ | 101,216 KB |
| 最終ジャッジ日時 | 2025-04-16 00:23:43 |
| 合計ジャッジ時間 | 5,260 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 18 |
ソースコード
MOD = 998244353
def main():
import sys
input = sys.stdin.read().split()
N = int(input[0])
K = int(input[1])
if N < 3:
print(0, 0)
return
# Initialize for i=2
prev_count = [[0] * K for _ in range(K)]
prev_sum = [[0] * K for _ in range(K)]
for a in range(K):
for b in range(K):
if a != b:
prev_count[a][b] = 1
prev_sum[a][b] = a + b
for i in range(3, N + 1):
current_count = [[0] * K for _ in range(K)]
current_sum = [[0] * K for _ in range(K)]
# Precompute prefix sums for each b_prev
prefix_count = [[0] * K for _ in range(K)]
prefix_sum = [[0] * K for _ in range(K)]
for b_prev in range(K):
# Compute prefix_count[b_prev][x]
prefix_count[b_prev][0] = prev_count[0][b_prev]
prefix_sum[b_prev][0] = prev_sum[0][b_prev]
for x in range(1, K):
prefix_count[b_prev][x] = (prefix_count[b_prev][x-1] + prev_count[x][b_prev]) % MOD
prefix_sum[b_prev][x] = (prefix_sum[b_prev][x-1] + prev_sum[x][b_prev]) % MOD
# Iterate over all (b_prev, c)
for b_prev in range(K):
for c in range(K):
if b_prev == c:
continue
sum_count = 0
sum_sum = 0
if b_prev > c:
# a_prev in 0..b_prev-1, exclude c
if b_prev == 0:
sum_count = 0
sum_sum = 0
else:
sum_count = prefix_count[b_prev][b_prev - 1]
sum_sum = prefix_sum[b_prev][b_prev - 1]
# Subtract if c is within the range
if c < b_prev:
sum_count = (sum_count - prev_count[c][b_prev]) % MOD
sum_sum = (sum_sum - prev_sum[c][b_prev]) % MOD
else:
# b_prev < c: a_prev in b_prev+1..K-1, exclude c
if b_prev + 1 >= K:
sum_count = 0
sum_sum = 0
else:
sum_count = (prefix_count[b_prev][K-1] - prefix_count[b_prev][b_prev]) % MOD
sum_sum = (prefix_sum[b_prev][K-1] - prefix_sum[b_prev][b_prev]) % MOD
# Subtract if c is in the range
if c >= b_prev + 1 and c < K:
sum_count = (sum_count - prev_count[c][b_prev]) % MOD
sum_sum = (sum_sum - prev_sum[c][b_prev]) % MOD
# Update current_count and current_sum
current_count[b_prev][c] = (current_count[b_prev][c] + sum_count) % MOD
current_sum[b_prev][c] = (current_sum[b_prev][c] + (sum_sum + sum_count * c) % MOD) % MOD
# Update prev_count and prev_sum for next iteration
prev_count, prev_sum = current_count, current_sum
ans_1 = 0
ans_2 = 0
for a in range(K):
for b in range(K):
ans_1 = (ans_1 + prev_count[a][b]) % MOD
ans_2 = (ans_2 + prev_sum[a][b]) % MOD
print(ans_1, ans_2)
if __name__ == "__main__":
main()
lam6er