結果
| 問題 | 
                            No.126 2基のエレベータ
                             | 
                    
| コンテスト | |
| ユーザー | 
                             lam6er
                         | 
                    
| 提出日時 | 2025-04-16 00:58:37 | 
| 言語 | PyPy3  (7.3.15)  | 
                    
| 結果 | 
                             
                                WA
                                 
                             
                            
                         | 
                    
| 実行時間 | - | 
| コード長 | 1,665 bytes | 
| コンパイル時間 | 186 ms | 
| コンパイル使用メモリ | 82,008 KB | 
| 実行使用メモリ | 53,596 KB | 
| 最終ジャッジ日時 | 2025-04-16 00:59:31 | 
| 合計ジャッジ時間 | 1,915 ms | 
| 
                            ジャッジサーバーID (参考情報)  | 
                        judge4 / judge3 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 3 | 
| other | AC * 21 WA * 6 | 
ソースコード
A, B, S = map(int, input().split())
def calculate_elevator_cost(A_pos, B_pos, S):
    # Case 1: Press down button
    if S == 1:
        elevator_down = 'A'
    else:
        dist_A_down = abs(A_pos - S)
        dist_B_down = abs(B_pos - S)
        if dist_A_down < dist_B_down:
            elevator_down = 'A'
        elif dist_B_down < dist_A_down:
            elevator_down = 'B'
        else:
            elevator_down = 'A'  # tie, A is prioritized
    
    # Case 2: Press up button
    dist_A_up = abs(A_pos - S)
    dist_B_up = abs(B_pos - S)
    if dist_A_up < dist_B_up:
        elevator_up = 'A'
    elif dist_B_up < dist_A_up:
        elevator_up = 'B'
    else:
        elevator_up = 'A'  # tie, A is prioritized
    
    # Calculate costs for each case
    min_cost = float('inf')
    
    # Evaluate elevator_down case
    if elevator_down == 'A':
        cost = abs(A_pos - S) + S
        min_cost = min(min_cost, cost)
    else:
        # B is called, need to transfer to A's initial position or 1 if A is 0
        X = A if A != 0 else 1
        cost_B = abs(B - S) + abs(S - X)
        cost_A = abs(A - X) + X
        total = cost_B + cost_A
        min_cost = min(min_cost, total)
    
    # Evaluate elevator_up case
    if elevator_up == 'A':
        cost = abs(A - S) + S
        min_cost = min(min_cost, cost)
    else:
        # B is called, need to transfer to A's initial position or 1 if A is 0
        X = A if A != 0 else 1
        cost_B = abs(B - S) + abs(S - X)
        cost_A = abs(A - X) + X
        total = cost_B + cost_A
        min_cost = min(min_cost, total)
    
    return min_cost
print(calculate_elevator_cost(A, B, S))
            
            
            
        
            
lam6er