結果

問題 No.1038 TreeAddQuery
ユーザー lam6er
提出日時 2025-04-16 15:31:03
言語 PyPy3
(7.3.15)
結果
TLE  
実行時間 -
コード長 2,400 bytes
コンパイル時間 216 ms
コンパイル使用メモリ 81,536 KB
実行使用メモリ 193,596 KB
最終ジャッジ日時 2025-04-16 15:36:08
合計ジャッジ時間 8,178 ms
ジャッジサーバーID
(参考情報)
judge3 / judge5
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 5 TLE * 1 -- * 18
権限があれば一括ダウンロードができます

ソースコード

diff #

import sys
from collections import deque

sys.setrecursionlimit(1 << 25)

def main():
    input = sys.stdin.read().split()
    ptr = 0
    N, Q = int(input[ptr]), int(input[ptr+1])
    ptr += 2

    adj = [[] for _ in range(N+1)]
    for _ in range(N-1):
        a = int(input[ptr])
        b = int(input[ptr+1])
        adj[a].append(b)
        adj[b].append(a)
        ptr += 2

    LOG = 20
    parent = [[-1]*(N+1) for _ in range(LOG)]
    depth = [0]*(N+1)

    root = 1
    q = deque([root])
    parent[0][root] = -1
    while q:
        u = q.popleft()
        for v in adj[u]:
            if parent[0][v] == -1 and v != parent[0][u]:
                parent[0][v] = u
                depth[v] = depth[u] + 1
                q.append(v)

    for k in range(1, LOG):
        for v in range(1, N+1):
            if parent[k-1][v] != -1:
                parent[k][v] = parent[k-1][parent[k-1][v]]

    def lca(u, v):
        if depth[u] < depth[v]:
            u, v = v, u
        for k in range(LOG-1, -1, -1):
            if depth[u] - (1 << k) >= depth[v]:
                u = parent[k][u]
        if u == v:
            return u
        for k in range(LOG-1, -1, -1):
            if parent[k][u] != parent[k][v]:
                u = parent[k][u]
                v = parent[k][v]
        return parent[0][u]

    def distance(u, v):
        a = lca(u, v)
        return depth[u] + depth[v] - 2 * depth[a]

    K = 300
    ans_small = [0]*(N+1)
    large_queries = []
    visited = [0]*(N+1)
    timestamp = 0

    for _ in range(Q):
        X_i = int(input[ptr])
        Y_i = int(input[ptr+1])
        Z_i = int(input[ptr+2])
        ptr += 3

        current_sum = ans_small[X_i]
        for (X_j, Y_j, Z_j) in large_queries:
            if Y_j >= distance(X_j, X_i):
                current_sum += Z_j

        print(current_sum)

        if Y_i <= K:
            timestamp += 1
            q = deque()
            q.append((X_i, 0))
            visited[X_i] = timestamp
            while q:
                u, dist = q.popleft()
                ans_small[u] += Z_i
                if dist < Y_i:
                    for v in adj[u]:
                        if visited[v] != timestamp:
                            visited[v] = timestamp
                            q.append((v, dist + 1))
        else:
            large_queries.append((X_i, Y_i, Z_i))

if __name__ == "__main__":
    main()
0