結果
| 問題 |
No.2178 Payable Magic Items
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-04-16 16:04:47 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 1,448 bytes |
| コンパイル時間 | 450 ms |
| コンパイル使用メモリ | 82,048 KB |
| 実行使用メモリ | 275,156 KB |
| 最終ジャッジ日時 | 2025-04-16 16:12:08 |
| 合計ジャッジ時間 | 6,302 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 TLE * 1 |
| other | AC * 4 TLE * 4 -- * 15 |
ソースコード
import sys
from itertools import product
def main():
N, K = map(int, sys.stdin.readline().split())
input_tuples = []
for _ in range(N):
s = sys.stdin.readline().strip()
t = tuple(int(c) for c in s)
input_tuples.append(t)
input_set = set(input_tuples)
# Initialize sum_dict with all possible tuples
sum_dict = {}
for t in product(*[range(5) for _ in range(K)]):
sum_dict[t] = 1 if t in input_set else 0
# Process each dimension to compute suffix sums
for d in range(K):
for current_d_val in range(4, -1, -1):
# Generate all possible combinations for the other K-1 dimensions
for other_dims in product(*[range(5) for _ in range(K-1)]):
# Split other_dims into left and right parts around the current dimension d
left = list(other_dims[:d])
right = list(other_dims[d:])
s_list = left + [current_d_val] + right
s = tuple(s_list)
if current_d_val < 4:
next_s_list = s_list.copy()
next_s_list[d] += 1
next_s = tuple(next_s_list)
sum_dict[s] += sum_dict[next_s]
# Count the number of tuples that can be sold
answer = 0
for x in input_tuples:
if sum_dict[x] >= 2:
answer += 1
print(answer)
if __name__ == "__main__":
main()
lam6er