結果
| 問題 |
No.1324 Approximate the Matrix
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-04-16 16:38:43 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,312 bytes |
| コンパイル時間 | 429 ms |
| コンパイル使用メモリ | 81,956 KB |
| 実行使用メモリ | 85,224 KB |
| 最終ジャッジ日時 | 2025-04-16 16:40:30 |
| 合計ジャッジ時間 | 5,231 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 10 WA * 32 |
ソースコード
import heapq
def main():
import sys
input = sys.stdin.read().split()
ptr = 0
N, K = int(input[ptr]), int(input[ptr+1])
ptr +=2
A = list(map(int, input[ptr:ptr+N]))
ptr +=N
B = list(map(int, input[ptr:ptr+N]))
ptr +=N
P = []
for _ in range(N):
row = list(map(int, input[ptr:ptr+N]))
P.append(row)
ptr +=N
Q = [[0]*N for _ in range(N)]
remaining_row = A.copy()
remaining_col = B.copy()
heap = []
for i in range(N):
for j in range(N):
if remaining_row[i] > 0 and remaining_col[j] > 0:
marginal_cost = 1 - 2 * P[i][j]
heapq.heappush(heap, (marginal_cost, -P[i][j], i, j))
while heap:
mc, neg_p, i, j = heapq.heappop(heap)
if remaining_row[i] <= 0 or remaining_col[j] <= 0:
continue
Q[i][j] +=1
remaining_row[i] -=1
remaining_col[j] -=1
new_mc = 2 * (Q[i][j] - P[i][j]) + 1
if remaining_row[i] > 0 and remaining_col[j] > 0:
heapq.heappush(heap, (new_mc, -P[i][j], i, j))
total =0
for i in range(N):
for j in range(N):
diff = Q[i][j] - P[i][j]
total += diff * diff
print(total)
if __name__ == "__main__":
main()
lam6er