結果
| 問題 |
No.3111 Toll Optimization
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2025-04-19 00:17:23 |
| 言語 | Python3 (3.13.1 + numpy 2.2.1 + scipy 1.14.1) |
| 結果 |
AC
|
| 実行時間 | 2,451 ms / 5,000 ms |
| コード長 | 1,528 bytes |
| コンパイル時間 | 171 ms |
| コンパイル使用メモリ | 12,416 KB |
| 実行使用メモリ | 89,940 KB |
| 最終ジャッジ日時 | 2025-04-19 00:18:13 |
| 合計ジャッジ時間 | 48,902 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 70 |
ソースコード
import heapq
def solve():
import sys
input = sys.stdin.read
data = input().split()
idx = 0
N = int(data[idx])
idx += 1
M = int(data[idx])
idx += 1
K = int(data[idx])
idx += 1
C = list(map(int, data[idx:idx+M]))
idx += M
adj = [[] for _ in range(N+1)]
for i in range(M):
u = int(data[idx])
idx += 1
v = int(data[idx])
idx += 1
adj[u].append((v, i))
adj[v].append((u, i))
INF = 1 << 60
dist = [[INF] * (K+1) for _ in range(N+1)]
dist[1][0] = 0
heap = []
heapq.heappush(heap, (0, 1, 0))
found = False
answer = INF
while heap:
current_cost, u, used = heapq.heappop(heap)
if u == N:
answer = min(answer, current_cost)
found = True
continue
if current_cost > dist[u][used]:
continue
for (v, idx_bridge) in adj[u]:
cost = C[idx_bridge]
# Option 1: do not use coupon
if dist[v][used] > current_cost + cost:
dist[v][used] = current_cost + cost
heapq.heappush(heap, (dist[v][used], v, used))
# Option 2: use coupon if possible
if used < K:
if dist[v][used + 1] > current_cost:
dist[v][used + 1] = current_cost
heapq.heappush(heap, (dist[v][used + 1], v, used + 1))
if found:
print(min(dist[N]))
else:
print(-1)
solve()