結果
| 問題 | 
                            No.3112 Decrement or Mod Game
                             | 
                    
| コンテスト | |
| ユーザー | 
                             aaaaaaaaaaa
                         | 
                    
| 提出日時 | 2025-04-19 12:08:48 | 
| 言語 | C++17  (gcc 13.3.0 + boost 1.87.0)  | 
                    
| 結果 | 
                             
                                TLE
                                 
                             
                            
                         | 
                    
| 実行時間 | - | 
| コード長 | 2,201 bytes | 
| コンパイル時間 | 1,434 ms | 
| コンパイル使用メモリ | 81,092 KB | 
| 実行使用メモリ | 133,832 KB | 
| 最終ジャッジ日時 | 2025-04-19 12:08:56 | 
| 合計ジャッジ時間 | 7,964 ms | 
| 
                            ジャッジサーバーID (参考情報)  | 
                        judge1 / judge5 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | -- * 3 | 
| other | TLE * 1 -- * 64 | 
ソースコード
#include <iostream>
#include <vector>
#include <string>
#include <map>
#include <utility> // for pair
using namespace std;
map<pair<long long, long long>, bool> memo;
// can_win(my, opp): Can the player whose turn it is, starting with numbers (my, opp), force a win?
bool can_win(long long my, long long opp) {
    // Base case 1: If my number is 0, I cannot make a move to win. This state implies I lost on a previous turn.
    if (my == 0) return false;
    // Base case 2 & Immediate Win: Check if I can make my number 0 this turn.
    if (my == 1) return true; // Operation 1: Subtract 1 to make it 0.
    if (my >= opp && my % opp == 0) return true; // Operation 2: Use Remainder to make it 0 (if applicable).
    // Check memoization to avoid recomputing states.
    if (memo.count({my, opp})) {
        return memo[{my, opp}];
    }
    bool res; // Result for the current state (my, opp)
    if (my < opp) {
 
        res = !can_win(opp, my - 1);
    } else { // my >= opp and my % opp != 0 (Immediate win handled above)
        long long q = my / opp; // Quotient
        long long r = my % opp; // Remainder (r > 0 because my % opp != 0)
        bool can_win_by_remainder = !can_win(opp, r);
        if (q == 1) { // Case: opp <= my < 2 * opp and my % opp != 0
            // Both Remainder (to (opp, r)) and Subtract (to (opp, my-1)) are important moves.
            // I win if either move leads to a state where the opponent loses.
            bool can_win_by_subtract = !can_win(opp, my - 1);
            res = can_win_by_remainder || can_win_by_subtract;
        } else { // Case: q >= 2 (my >= 2 * opp)
            res = can_win_by_remainder || (q % 2 == 1);
        }
    }
    // Store the computed result in the memoization table for the current state (my, opp)
    return memo[{my, opp}] = res;
}
int main() {
    // Optimize input/output operations
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    long long A, B;
    cin >> A >> B;
    // Alice starts the game with numbers A and B.
    // Alice wins if can_win(A, B) is true.
    if (can_win(A, B)) {
        cout << "Alice" << endl;
    } else {
        cout << "Bob" << endl;
    }
    return 0;
}
            
            
            
        
            
aaaaaaaaaaa