結果
問題 |
No.3112 Decrement or Mod Game
|
ユーザー |
![]() |
提出日時 | 2025-04-19 12:08:48 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
TLE
|
実行時間 | - |
コード長 | 2,201 bytes |
コンパイル時間 | 1,434 ms |
コンパイル使用メモリ | 81,092 KB |
実行使用メモリ | 133,832 KB |
最終ジャッジ日時 | 2025-04-19 12:08:56 |
合計ジャッジ時間 | 7,964 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | -- * 3 |
other | TLE * 1 -- * 64 |
ソースコード
#include <iostream> #include <vector> #include <string> #include <map> #include <utility> // for pair using namespace std; map<pair<long long, long long>, bool> memo; // can_win(my, opp): Can the player whose turn it is, starting with numbers (my, opp), force a win? bool can_win(long long my, long long opp) { // Base case 1: If my number is 0, I cannot make a move to win. This state implies I lost on a previous turn. if (my == 0) return false; // Base case 2 & Immediate Win: Check if I can make my number 0 this turn. if (my == 1) return true; // Operation 1: Subtract 1 to make it 0. if (my >= opp && my % opp == 0) return true; // Operation 2: Use Remainder to make it 0 (if applicable). // Check memoization to avoid recomputing states. if (memo.count({my, opp})) { return memo[{my, opp}]; } bool res; // Result for the current state (my, opp) if (my < opp) { res = !can_win(opp, my - 1); } else { // my >= opp and my % opp != 0 (Immediate win handled above) long long q = my / opp; // Quotient long long r = my % opp; // Remainder (r > 0 because my % opp != 0) bool can_win_by_remainder = !can_win(opp, r); if (q == 1) { // Case: opp <= my < 2 * opp and my % opp != 0 // Both Remainder (to (opp, r)) and Subtract (to (opp, my-1)) are important moves. // I win if either move leads to a state where the opponent loses. bool can_win_by_subtract = !can_win(opp, my - 1); res = can_win_by_remainder || can_win_by_subtract; } else { // Case: q >= 2 (my >= 2 * opp) res = can_win_by_remainder || (q % 2 == 1); } } // Store the computed result in the memoization table for the current state (my, opp) return memo[{my, opp}] = res; } int main() { // Optimize input/output operations ios_base::sync_with_stdio(false); cin.tie(NULL); long long A, B; cin >> A >> B; // Alice starts the game with numbers A and B. // Alice wins if can_win(A, B) is true. if (can_win(A, B)) { cout << "Alice" << endl; } else { cout << "Bob" << endl; } return 0; }