結果
問題 |
No.2403 "Eight" Bridges of Königsberg
|
ユーザー |
![]() |
提出日時 | 2025-04-24 12:25:54 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,773 bytes |
コンパイル時間 | 338 ms |
コンパイル使用メモリ | 82,032 KB |
実行使用メモリ | 92,020 KB |
最終ジャッジ日時 | 2025-04-24 12:26:26 |
合計ジャッジ時間 | 4,951 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 10 WA * 21 |
ソースコード
import sys from collections import deque def main(): sys.setrecursionlimit(1 << 25) N, M = map(int, sys.stdin.readline().split()) out_degree = [0] * (N + 1) in_degree = [0] * (N + 1) adj = [[] for _ in range(N + 1)] # Undirected adjacency list for BFS for _ in range(M): u, v = map(int, sys.stdin.readline().split()) out_degree[u] += 1 in_degree[v] += 1 adj[u].append(v) adj[v].append(u) # For undirected connectivity check # Compute weak connected components using BFS visited = [False] * (N + 1) C = 0 for v in range(1, N + 1): if not visited[v]: C += 1 q = deque() q.append(v) visited[v] = True while q: u = q.popleft() for nei in adj[u]: if not visited[nei]: visited[nei] = True q.append(nei) # Calculate d for each vertex d = [0] * (N + 1) for v in range(1, N + 1): d[v] = out_degree[v] - in_degree[v] # Compute sum_case1 sum_case1 = sum(max(0, dv) for dv in d[1:]) # Determine sum_case2 has_positive = any(dv >= 1 for dv in d[1:]) has_negative = any(dv <= -1 for dv in d[1:]) if has_positive and has_negative: sum_case2 = sum_case1 - 1 elif has_positive: sum_case2 = sum_case1 else: sum_case2 = float('inf') K_degree = min(sum_case1, sum_case2) if K_degree == float('inf'): print(-1) return # Check connectivity condition if C == 1: print(K_degree) else: if K_degree >= C - 1: print(K_degree) else: print(-1) if __name__ == '__main__': main()