結果
問題 |
No.3129 Multiple of Twin Subarray
|
ユーザー |
![]() |
提出日時 | 2025-04-25 21:51:20 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,743 bytes |
コンパイル時間 | 480 ms |
コンパイル使用メモリ | 82,352 KB |
実行使用メモリ | 141,260 KB |
最終ジャッジ日時 | 2025-04-25 21:51:30 |
合計ジャッジ時間 | 9,233 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 29 WA * 17 |
ソースコード
n=int(input()) a=list(map(int,input().split())) ans=-10**20 ca=a+[0] for i in range(n): ca[i]+=ca[i-1] q=[0]*n l=0 for i in range(n): q[i]=ca[i]-l l=min(l,ca[i]) ql=q[:] ca=a[::-1]+[0] for i in range(n): ca[i]+=ca[i-1] q=[0]*n l=0 for i in range(n): q[i]=ca[i]-l l=min(l,ca[i]) qr=q[:] qr=qr[::-1] qr1=qr[:] qr2=qr[:] for i in range(n-1): qr1[i]=max(qr1[i],qr1[i+1]) qr2[i]=min(qr2[i],qr2[i+1]) for i in range(n-1): ans=max(ans,ql[i]*qr1[i+1],ql[i]*qr2[i+1]) ca=a+[0] for i in range(n): ca[i]+=ca[i-1] q=[0]*n l=0 for i in range(n): q[i]=ca[i]-l l=max(l,ca[i]) ql=q[:] ca=a[::-1]+[0] for i in range(n): ca[i]+=ca[i-1] q=[0]*n l=0 for i in range(n): q[i]=ca[i]-l l=min(l,ca[i]) qr=q[:] qr=qr[::-1] qr1=qr[:] qr2=qr[:] for i in range(n-1): qr1[i]=max(qr1[i],qr1[i+1]) qr2[i]=min(qr2[i],qr2[i+1]) for i in range(n-1): ans=max(ans,ql[i]*qr1[i+1],ql[i]*qr2[i+1]) ca=a+[0] for i in range(n): ca[i]+=ca[i-1] q=[0]*n l=0 for i in range(n): q[i]=ca[i]-l l=min(l,ca[i]) ql=q[:] ca=a[::-1]+[0] for i in range(n): ca[i]+=ca[i-1] q=[0]*n l=0 for i in range(n): q[i]=ca[i]-l l=max(l,ca[i]) qr=q[:] qr=qr[::-1] qr1=qr[:] qr2=qr[:] for i in range(n-1): qr1[i]=max(qr1[i],qr1[i+1]) qr2[i]=min(qr2[i],qr2[i+1]) for i in range(n-1): ans=max(ans,ql[i]*qr1[i+1],ql[i]*qr2[i+1]) ca=a+[0] for i in range(n): ca[i]+=ca[i-1] q=[0]*n l=0 for i in range(n): q[i]=ca[i]-l l=max(l,ca[i]) ql=q[:] ca=a[::-1]+[0] for i in range(n): ca[i]+=ca[i-1] q=[0]*n l=0 for i in range(n): q[i]=ca[i]-l l=max(l,ca[i]) qr=q[:] qr=qr[::-1] qr1=qr[:] qr2=qr[:] for i in range(n-1): qr1[i]=max(qr1[i],qr1[i+1]) qr2[i]=min(qr2[i],qr2[i+1]) for i in range(n-1): ans=max(ans,ql[i]*qr1[i+1],ql[i]*qr2[i+1]) print(ans)