結果

問題 No.3063 Circle Balancing
コンテスト
ユーザー hos.lyric
提出日時 2025-04-26 23:34:13
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 208 ms / 3,000 ms
コード長 6,111 bytes
コンパイル時間 1,351 ms
コンパイル使用メモリ 118,720 KB
実行使用メモリ 44,244 KB
最終ジャッジ日時 2025-04-26 23:34:21
合計ジャッジ時間 7,487 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 27
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:185:12: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
  185 |       scanf("%d", &A[i]);
      |       ~~~~~^~~~~~~~~~~~~

ソースコード

diff # 

#include <cassert>
#include <cmath>
#include <cstdint>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <bitset>
#include <chrono>
#include <complex>
#include <deque>
#include <functional>
#include <iostream>
#include <limits>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>

using namespace std;

using Int = long long;

template <class T1, class T2> ostream &operator<<(ostream &os, const pair<T1, T2> &a) { return os << "(" << a.first << ", " << a.second << ")"; };
template <class T> ostream &operator<<(ostream &os, const vector<T> &as) { const int sz = as.size(); os << "["; for (int i = 0; i < sz; ++i) { if (i >= 256) { os << ", ..."; break; } if (i > 0) { os << ", "; } os << as[i]; } return os << "]"; }
template <class T> void pv(T a, T b) { for (T i = a; i != b; ++i) cerr << *i << " "; cerr << endl; }
template <class T> bool chmin(T &t, const T &f) { if (t > f) { t = f; return true; } return false; }
template <class T> bool chmax(T &t, const T &f) { if (t < f) { t = f; return true; } return false; }
#define COLOR(s) ("\x1b[" s "m")


// T: monoid representing information of an interval.
//   T()  should return the identity.
//   T(S s)  should represent a single element of the array.
//   T::pull(const T &l, const T &r)  should pull two intervals.
template <class T> struct SegmentTreePoint {
  int logN, n;
  vector<T> ts;
  SegmentTreePoint() : logN(0), n(0) {}
  explicit SegmentTreePoint(int n_) {
    for (logN = 0, n = 1; n < n_; ++logN, n <<= 1) {}
    ts.resize(n << 1);
  }
  template <class S> explicit SegmentTreePoint(const vector<S> &ss) {
    const int n_ = ss.size();
    for (logN = 0, n = 1; n < n_; ++logN, n <<= 1) {}
    ts.resize(n << 1);
    for (int i = 0; i < n_; ++i) at(i) = T(ss[i]);
    build();
  }
  T &at(int i) {
    return ts[n + i];
  }
  void build() {
    for (int u = n; --u; ) pull(u);
  }

  inline void pull(int u) {
    ts[u].pull(ts[u << 1], ts[u << 1 | 1]);
  }

  // Changes the value of point a to s.
  template <class S> void change(int a, const S &s) {
    assert(0 <= a); assert(a < n);
    ts[a += n] = T(s);
    for (; a >>= 1; ) pull(a);
  }

  // Applies T::f(args...) to point a.
  template <class F, class... Args>
  void ch(int a, F f, Args &&... args) {
    assert(0 <= a); assert(a < n);
    (ts[a += n].*f)(args...);
    for (; a >>= 1; ) pull(a);
  }

  // Calculates the product for [a, b).
  T get(int a, int b) {
    assert(0 <= a); assert(a <= b); assert(b <= n);
    if (a == b) return T();
    T prodL, prodR, t;
    for (a += n, b += n; a < b; a >>= 1, b >>= 1) {
      if (a & 1) { t.pull(prodL, ts[a++]); prodL = t; }
      if (b & 1) { t.pull(ts[--b], prodR); prodR = t; }
    }
    t.pull(prodL, prodR);
    return t;
  }

  // Calculates T::f(args...) of a monoid type for [a, b).
  //   op(-, -)  should calculate the product.
  //   e()  should return the identity.
  template <class Op, class E, class F, class... Args>
#if __cplusplus >= 201402L
  auto
#else
  decltype((std::declval<T>().*F())())
#endif
  get(int a, int b, Op op, E e, F f, Args &&... args) {
    assert(0 <= a); assert(a <= b); assert(b <= n);
    if (a == b) return e();
    auto prodL = e(), prodR = e();
    for (a += n, b += n; a < b; a >>= 1, b >>= 1) {
      if (a & 1) prodL = op(prodL, (ts[a++].*f)(args...));
      if (b & 1) prodR = op((ts[--b].*f)(args...), prodR);
    }
    return op(prodL, prodR);
  }

  // Find min b s.t. T::f(args...) returns true,
  // when called for the partition of [a, b) from left to right.
  //   Returns n + 1 if there is no such b.
  template <class F, class... Args>
  int findRight(int a, F f, Args &&... args) {
    assert(0 <= a); assert(a <= n);
    if ((T().*f)(args...)) return a;
    if (a == n) return n + 1;
    a += n;
    for (; ; a >>= 1) if (a & 1) {
      if ((ts[a].*f)(args...)) {
        for (; a < n; ) {
          if (!(ts[a <<= 1].*f)(args...)) ++a;
        }
        return a - n + 1;
      }
      ++a;
      if (!(a & (a - 1))) return n + 1;
    }
  }

  // Find max a s.t. T::f(args...) returns true,
  // when called for the partition of [a, b) from right to left.
  //   Returns -1 if there is no such a.
  template <class F, class... Args>
  int findLeft(int b, F f, Args &&... args) {
    assert(0 <= b); assert(b <= n);
    if ((T().*f)(args...)) return b;
    if (b == 0) return -1;
    b += n;
    for (; ; b >>= 1) if ((b & 1) || b == 2) {
      if ((ts[b - 1].*f)(args...)) {
        for (; b <= n; ) {
          if (!(ts[(b <<= 1) - 1].*f)(args...)) --b;
        }
        return b - n - 1;
      }
      --b;
      if (!(b & (b - 1))) return -1;
    }
  }
};  // SegmentTreePoint<T>

////////////////////////////////////////////////////////////////////////////////


// min ((# left -) + (# right +))

struct Node {
  // -, +
  int a, b;
  int mn;
  Node() : a(0), b(0), mn(0) {}
  Node(int val) : a(val < 0), b(val > 0), mn(0) {}
  void pull(const Node &l, const Node &r) {
    a = l.a + r.a;
    b = l.b + r.b;
    mn = min(l.mn + r.b, l.a + r.mn);
  }
};

int N;
vector<int> A;

int main() {
  for (; ~scanf("%d", &N); ) {
    A.resize(N);
    for (int i = 0; i < N; ++i) {
      scanf("%d", &A[i]);
    }
    
    vector<vector<int>> iss(N + 1);
    for (int i = 0; i < N; ++i) iss[A[i]].push_back(i);
    
    SegmentTreePoint<Node> seg(vector<int>(N + N, +1));
    int ans = 2*N;
    for (int a = 1; a <= N; ++a) if (iss[a].size()) {
      const auto &is = iss[a];
      const int isLen = is.size();
      int cost = 0;
      for (int j = 0; j < isLen; ++j) {
        const int l = is[j];
        const int r = (j == isLen - 1) ? (N + is[0]) : is[j + 1];
        const auto res = seg.get(l + 1, r);
// cerr<<a<<" "<<l<<" "<<r<<": "<<res.mn<<endl;
        cost += (r - l - 1) + res.mn;
      }
      chmin(ans, cost);
      for (const int i : is) {
        seg.change(i, -1);
        seg.change(N + i, -1);
      }
    }
    printf("%d\n", ans);
  }
  return 0;
}
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