結果

問題 No.3058 Deque and Brackets
ユーザー anago-pie
提出日時 2025-04-27 20:59:59
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
MLE  
実行時間 -
コード長 10,351 bytes
コンパイル時間 4,174 ms
コンパイル使用メモリ 313,148 KB
実行使用メモリ 824,960 KB
最終ジャッジ日時 2025-04-27 21:00:14
合計ジャッジ時間 12,260 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 7 MLE * 1 -- * 14
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ソースコード

diff # 

#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for(int i=0; i<n; i++)
#define debug 0
#define YES cout << "Yes" << endl;
#define NO cout << "No" << endl;
using ll = long long;
using ld = long double;
const int mod = 998244353;
const int MOD = 1000000007;
const double pi = atan2(0, -1);
const int inf = 1 << 31 - 1;
const ll INF = 1LL << 63 - 1;
#include <time.h>
#include <chrono>

//vectorの中身を空白区切りで出力
template<typename T>
void printv(vector<T> v) {
	for (int i = 0; i < v.size(); i++) {
		cout << v[i];
		if (i < v.size() - 1) {
			cout << " ";
		}
	}
	cout << endl;
}

//vectorの中身を改行区切りで出力
template<typename T>
void print1(vector<T> v) {
	for (auto x : v) {
		cout << x << endl;
	}
}

//二次元配列を出力
template<typename T>
void printvv(vector<vector<T>> vv) {
	for (vector<T> v : vv) {
		printv(v);
	}
}

//vectorを降順にソート
template<typename T>
void rsort(vector<T>& v) {
	sort(v.begin(), v.end());
	reverse(v.begin(), v.end());
}

//昇順priority_queueを召喚
template<typename T>
struct rpriority_queue {
	priority_queue<T, vector<T>, greater<T>> pq;

	void push(T x) {
		pq.push(x);
	}

	void pop() {
		pq.pop();
	}

	T top() {
		return pq.top();
	}

	size_t size() {
		return pq.size();
	}

	bool empty() {
		return pq.empty();
	}
};

//mod mod下で逆元を算出する
//高速a^n計算(mod ver.)
ll power(ll a, ll n) {
	if (n == 0) {
		return 1;
	}
	else if (n % 2 == 0) {
		ll x = power(a, n / 2);
		x *= x;
		x %= mod;
		return x;
	}
	else {
		ll x = power(a, n - 1);
		x *= a;
		x %= mod;
		return x;
	}
}
//フェルマーの小定理を利用
ll modinv(ll p) {
	return power(p, mod - 2) % mod;
}

//Mexを求める
struct Mex {
	map<int, int> mp;
	set<int> s;
	Mex(int Max) {
		for (int i = 0; i <= Max; i++) {
			s.insert(i);
		}
	}

	int _mex = 0;
	void Input(int x) {
		mp[x]++;
		s.erase(x);
		if (_mex == x) {
			_mex = *begin(s);
		}
	}

	void Remove(int x) {
		if (mp[x] == 0) {
			cout << "Mex ERROR!: NO VALUE WILL BE REMOVED" << endl;
		}
		mp[x]--;
		if (mp[x] == 0) {
			s.insert(x);
			if (*begin(s) == x) {
				_mex = x;
			}
		}
	}

	int mex() {
		return _mex;
	}
};

//条件分岐でYes/Noを出力するタイプのやつ
void YN(bool true_or_false) {
	cout << (true_or_false ? "Yes" : "No") << endl;
}

//最大公約数(ユークリッドの互除法）
ll gcd(ll a, ll b) {
	if (b > a) {
		swap(a, b);
	}
	while (a % b != 0) {
		ll t = a;
		a = b;
		b = t % b;
	}
	return b;
}

//最小公倍数（gcdを定義しておく）
ll lcm(ll a, ll b) {
	ll g = gcd(a, b);
	ll x = (a / g) * b;
	return x;
}

struct UnionFind {
	vector<int> par;
	UnionFind(int N) {
		rep(i, N) {
			par.push_back(i);
		}
	}

	int root(int x) {
		if (par[x] == x) {
			return x;
		}
		else {
			return par[x] = root(par[x]);
		}
	}

	bool isSame(int x, int y) {
		return root(x) == root(y);
	}

	void Union(int x, int y) {
		if (!isSame(x, y)) {
			int rx = root(x), ry = root(y);
			if (rx > ry) {
				par[rx] = ry;
			}
			else {
				par[ry] = rx;
			}
		}
	}
};

//最大流問題を解く構造体(Ford-Fulkerson法.O(FE))
struct maxflow {
	struct Edge {
		int to, rev;
		ll capacity, init_capacity;
		Edge(int _to, int _rev, ll _capacity) :to(_to), rev(_rev), capacity(_capacity), init_capacity(_capacity) {};
	};
	
	vector<vector<Edge>> Graph;

	maxflow(int MAX_V) {
		Graph.assign(MAX_V, {});
	}

	void input(int from, int to, ll capacity) {
		int e_id = Graph[from].size();
		int r_id = Graph[to].size();
		Graph[from].push_back(Edge(to, r_id, capacity));
		Graph[to].push_back(Edge(from, e_id, 0));
	}

	Edge& rev_Edge(Edge& edge) {
		return Graph[edge.to][edge.rev];
	}

	vector<bool> visited;
	ll dfs(int now, int g, ll flow) {
		visited[now] = true;
		if (now == g) {
			return flow;
		}
		else {
			ll f = 0;
			ll res_flow = flow;
			for (Edge& edge : Graph[now]) {
				if (!visited[edge.to] && edge.capacity > 0) {
					ll f_delta = dfs(edge.to, g, min(res_flow, edge.capacity));	
					edge.capacity -= f_delta;
					rev_Edge(edge).capacity += f_delta;
					f += f_delta;
					res_flow -= f_delta;
					if (res_flow == 0) {
						break;
					}
				}
			}
			return f;
		}
	}

	void flowing(int s, int g, ll init_flow = INF) {
		bool cont = true;
		while (cont) {
			visited.assign(Graph.size(), false);
			ll flow = dfs(s, g, init_flow);
			init_flow -= flow;
			if (flow == 0) {
				cont = false;
			}
		}
	}

	ll get_flow(int g) {
		ll flow = 0;
		for (Edge& edge : Graph[g]) {
			Edge& rev_edge = rev_Edge(edge);
			ll tmp_flow = rev_edge.init_capacity - rev_edge.capacity;
			if (tmp_flow > 0) {
				flow += tmp_flow;
			}
		}
		return flow;
	}

	vector<tuple<int, int, ll>> flowing_edges() {
		vector<tuple<int, int, ll>> vec;
		rep(from, Graph.size()) {
			for (Edge& edge : Graph[from]) {
				ll flow = edge.init_capacity - edge.capacity;
				if (flow > 0) {
					vec.push_back({ from,edge.to,flow });
				}
			}
		}
		return vec;
	}

	vector<bool> min_cut(int s) {
		vector<bool> check(Graph.size(), false);
		queue<int> q;
		q.push(s);
		check[s] = true;
		while (!q.empty()) {
			int now = q.front();
			q.pop();
			for (Edge& edge : Graph[now]) {
				if (edge.capacity > 0 && !check[edge.to]) {
					check[edge.to] = true;
					q.push(edge.to);
				}
			}
		}
		return check;
	}

	vector<tuple<int, int, ll>> min_cut_edges(int s) {
		vector<bool> cut = min_cut(s);
		vector<tuple<int, int, ll>> vec;
		for (int from = 0; from < Graph.size(); from++) {
			if (cut[from]) {
				for (Edge& edge : Graph[from]) {
					if (!cut[edge.to] && edge.init_capacity > 0) {
						vec.push_back({ from,edge.to,edge.init_capacity });
					}
				}
			}
		}
		return vec;
	}

	void reset() {
		for (int from = 0; from < Graph.size(); from++) {
			for (Edge& edge : Graph[from]) {
				edge.capacity = edge.init_capacity;
			}
		}
	}
};

//Dinic法でのmax-flow。最大マッチングなど辺のキャパシティが小さい場合には高速
struct Dinic {
	struct Edge {
		int to, rev;
		ll capacity, init_capacity;
		ld cost;
		Edge(int _to, int _rev, ll _capacity,ld _cost) :to(_to), rev(_rev), capacity(_capacity),init_capacity(_capacity),cost(_cost) {};
	};

	vector<vector<Edge>> Graph;

	Edge& rev_Edge(Edge& edge) {
		return Graph[edge.to][edge.rev];
	}
	vector<int> level,itr;

	Dinic(int MAX_V) {
		Graph.assign(MAX_V, {});
	}

	void input(int _from, int _to, ll _capacity,ld _cost) {
		int e_id = Graph[_from].size(), r_id = Graph[_to].size();
		Graph[_from].push_back(Edge(_to, r_id, _capacity,_cost));
		Graph[_to].push_back(Edge(_from, e_id, 0LL,_cost));
	}

	void bfs(int s, int g, ld val) {
		level.assign(Graph.size(), -1);
		level[s] = 0;
		queue<int> q;
		q.push(s);
		while (!q.empty()) {
			int now = q.front();
			q.pop();
			if (now == g) {
				continue;
			}
			for (Edge &e : Graph[now]) {
				if (level[e.to] == -1 && e.capacity > 0 && e.cost<=val) {
					level[e.to] = level[now] + 1;
					q.push(e.to);
				}
			}
		}
	}

	ll dfs(int now, int g, ll flow, ld val) {
		if (now == g) {
			return flow;
		}
		else if (level[now] >= level[g]) {
			return 0; //gよりも深い場所に行こうとしたら終わり。flow=0を返す
		}
		else {
			ll res_flow = flow;
			ll f = 0;
			for (int &i = itr[now]; i < Graph[now].size(); i++) {
				Edge& edge = Graph[now][i];
				if (level[edge.to] == level[now] + 1 && edge.capacity > 0 && edge.cost<=val) {
					ll f_delta = dfs(edge.to, g, min(res_flow, edge.capacity), val);
					edge.capacity -= f_delta;
					rev_Edge(edge).capacity += f_delta;
					res_flow -= f_delta;
					f += f_delta;
					if (res_flow == 0) {
						break;
					}
				}
			}
			return f; //行先が無い場合はflow=0を返す
		}
	}

	void flowing(int s, int g, ll init_flow = INF, ld val=0) {
		bool cont1 = true;
		while (cont1) {
			bfs(s, g,val);
			if (level[g] == -1) {
				cont1 = false;
			}
			else {
				bool cont2 = true;
				while (cont2) {
					itr.assign(Graph.size(), 0);
					ll flow = dfs(s, g, init_flow,val);
					init_flow -= flow;
					if (flow == 0) {
						cont2 = false;
					}
				}
			}
		}
	}

	ll get_flow(int g) {
		ll flow = 0;
		for (Edge& edge : Graph[g]) {
			flow += max(0LL, rev_Edge(edge).init_capacity - rev_Edge(edge).capacity);
		}
		return flow;
	}

	vector<tuple<int, int, ll>> flowing_edges(){
		vector<tuple<int,int,ll>> vec;
		for (int from = 0; from < Graph.size(); from++) {
			for (Edge& edge : Graph[from]) {
				if (edge.init_capacity - edge.capacity > 0) {
					vec.push_back({ from,edge.to,edge.init_capacity - edge.capacity });
				}
			}
		}
		return vec;
	}

	vector<bool> min_cut(int s) {
		vector<bool> check(Graph.size(), false);
		queue<int> q;
		q.push(s);
		check[s] = true;
		while (!q.empty()) {
			int now = q.front();
			q.pop();
			for (Edge& edge : Graph[now]) {
				if (edge.capacity > 0 && !check[edge.to]) {
					check[edge.to] = true;
					q.push(edge.to);
				}
			}
		}
		return check;
	}

	vector<tuple<int, int, ll>> min_cut_edges(int s) {
		vector<bool> cut = min_cut(s);
		vector<tuple<int, int, ll>> vec;
		for (int from = 0; from < Graph.size(); from++) {
			if (cut[from]) {
				for (Edge& edge : Graph[from]) {
					if (!cut[edge.to] && edge.init_capacity > 0) {
						vec.push_back({ from,edge.to,edge.init_capacity });
					}
				}
			}
		}
		return vec;
	}

	void reset() {
		for (int from = 0; from < Graph.size(); from++) {
			for (Edge& edge : Graph[from]) {
				edge.capacity = edge.init_capacity;
			}
		}
	}
};

int main() {
	int N;
	cin >> N;
	map<int, map<int, map<int, ll>>> dp;
	dp[0][0][0] = 0;
	rep(i, N*2) {
		char c;
		ll L, R;
		cin >> c >> L >> R;
		for (auto &p : dp[i]) {
			for (auto &q : p.second) {
				int l = p.first;
				int r = q.first;
				ll m = q.second;
				if (c == ')') {
					if (r == 0) {
						dp[i + 1][l + 1][0] = max(dp[i + 1][l + 1][0], m + max(L, R));
					}
					else {
						if (r > 0) {
							dp[i + 1][l][r - 1] = max(dp[i + 1][l][r - 1], m + R);
						}
						dp[i + 1][l + 1][r] = max(dp[i + 1][l + 1][r], m + L);
					}
				}
				else {
					if (l == 0) {
						dp[i + 1][0][r + 1] = max(dp[i+1][0][r + 1], m + max(L, R));
					}
					else {
						if (l > 0) {
							dp[i + 1][l - 1][r] = max(dp[i + 1][l - 1][r], m + L);
						}
						dp[i + 1][l][r + 1] = max(dp[i + 1][l][r + 1], m + R);
					}
				}
			}
		}
	}

	cout << dp[N*2][0][0] << endl;

	
}
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