結果
| 問題 |
No.577 Prime Powerful Numbers
|
| ユーザー |
|
| 提出日時 | 2025-05-02 10:39:39 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 2,175 bytes |
| コンパイル時間 | 2,098 ms |
| コンパイル使用メモリ | 195,296 KB |
| 実行使用メモリ | 7,840 KB |
| 最終ジャッジ日時 | 2025-05-02 10:39:49 |
| 合計ジャッジ時間 | 8,204 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 9 WA * 1 |
ソースコード
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int inf = 0x3f3f3f3f;
int prime[1000010],len;
bitset<10000010>vis;
inline void modadd(ll &a,ll b,const ll MOD){a += b;if(a >= MOD){a -= MOD;}}
ll qmul(ll A,ll B,const ll MOD){
ll res = 0;
while(B){
if(B&1){modadd(res,A,MOD);}
modadd(A,A,MOD);
B >>= 1;
}
return res;
}
ll qpow(ll A,ll B,const ll MOD){
ll res = 1;
while(B){
if(B&1){res = qmul(res,A,MOD);}
A = qmul(A,A,MOD);
B >>= 1;
}
return res;
}
void init(){
vis[0] = vis[1] = 1;
for(int i = 2;i <= 10000000;++i){
if(!vis[i]){prime[++len] = i;}
for(int j = 1;j <= len&&prime[j]*i <= 10000000;++j){
vis[prime[j]*i] = 1;
if(i%prime[j] == 0){break;}
}
}
for(int i = 3500;i >= 2;--i){
if(vis[i]){continue;}
for(ll j = i*i;j <= 10000000;j *= i){vis[j] = 0;}
}
}
bool Miller_Rabin(const ll x,const ll base){
ll u = x-1;
while(!(u&1)){u >>= 1;}
ll v = qpow(base,u,x);
if(v == 1){return 1;}
while(u < x-1){
if(v == x-1){return 1;}
v = qmul(v,v,x);
u <<= 1;
}
return 0;
}
bool isprime(ll x){
if(x <= 1){return 0;}
ll checkbase[8] = {2,3,5,7,11,13,17,37};
for(int i = 0;i < 8;++i){
if(x == checkbase[i]){return 1;}
if(x%checkbase[i] == 0){return 0;}
if(!Miller_Rabin(x,checkbase[i])){return 0;}
}
return 1;
}
bool check(ll x){
if(x <= 10000000){return (!vis[x]);}
if(isprime(x)){return 1;}
for(int i = 1;i <= len;++i){
if(x%prime[i] == 0){
while(x > 1&&x%prime[i] == 0){x /= prime[i];}
return x == 1;
}
}
ll tmp = sqrt(x);
if(tmp*tmp == x&&isprime(tmp)){return 1;}
if((tmp+1)*(tmp+1) == x&&isprime((tmp+1))){return 1;}
return 0;
}
void solve(){
ll N;cin >> N;
if(N&1){
for(ll j = 2;j < N;j <<= 1){if(check(N-j)){cout << "Yes\n";return;}}
cout << "No\n";return;
}
if(N == 2){cout << "No\n";}
cout << "Yes\n";return;
}
int main(){
ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
// freopen("number.in","r",stdin);
// freopen("number.out","w",stdout);
int T = 1;cin >> T;init();
for(int i = 1;i <= T;++i){solve();}
return 0;
}