結果
| 問題 |
No.584 赤、緑、青の色塗り
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2025-05-04 15:54:48 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 33 ms / 2,000 ms |
| コード長 | 2,071 bytes |
| コンパイル時間 | 2,235 ms |
| コンパイル使用メモリ | 193,668 KB |
| 実行使用メモリ | 73,884 KB |
| 最終ジャッジ日時 | 2025-05-04 15:54:52 |
| 合計ジャッジ時間 | 3,631 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 6 |
| other | AC * 14 |
ソースコード
# include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
# define int long long
# define lc u << 1
# define rc u << 1 | 1
# define fi first
# define se second
# define endl "\n"
const int N = 3005, mod = 1000000007;
int n, R, G, B;
int quick_pow (int a, int B = mod - 2)
{
int ans = 1;
while (B)
{
if (B & 1)
ans = 1ll * ans * a % mod;
a = a * a % mod, B >>= 1;
}
return ans;
}
int C[N][N];
void init ()
{
C[0][0] = 1;
for (int S2 = 1; S2 < N; S2 ++ )
{
C[S2][0] = C[S2 - 1][0];
for (int r2 = 1; r2 <= S2; r2 ++ )
C[S2][r2] = (C[S2 - 1][r2] + C[S2 - 1][r2 - 1]) % mod;
}
}
void solve ()
{
init ();
cin >> n >> R >> G >> B;
int ans = 0;
for (int S2 = 0; S2 <= n; S2 ++ )
{
if (S2 * 2 > R + G + B)
break;
for (int r2 = 0; r2 <= min (S2, R); r2 ++ )
{
int lft = S2 - r2;
if (lft > min (G, B))
continue;
int rg = G - lft;
int rb = B - lft;
if (rg < 0 || rb < 0)
continue;
int tmp = 1;
int ri = R + G + B - 2 * S2;
int want = ri;
int need = 2 * want + 3 * S2 - 1;
if (need > n)
continue;
int can = n - need;
tmp = tmp * C[S2][r2] % mod;
tmp = tmp * C[can + S2 + want][can] % mod;
tmp = tmp * C[S2 + want][S2] % mod;
tmp = tmp * quick_pow (2, S2) % mod;
tmp = tmp * C[want][R - r2] % mod;
tmp = tmp * C[rg + rb][rg] % mod;
ans = (ans + tmp) % mod;
}
}
cout << ans % mod << endl;
}
signed main ()
{
// freopen ("RGB.in", "r", stdin); freopen ("RGB.out", "w", stdout);
double t1 = clock ();
ios::sync_with_stdio (0); cin.tie (0); cout.tie (0);
int T = 1;
// cin >> T;
while (T -- )
{
solve ();
cout.flush ();
}
double t2 = clock ();
// cerr << "used time: " << (double)(t2 - t1) / (double)CLOCKS_PER_SEC << endl;
return 0;
}