結果

問題 No.3098 Linear Reversi
コンテスト
ユーザー qwewe
提出日時 2025-05-14 12:58:33
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 1,662 bytes
コンパイル時間 170 ms
コンパイル使用メモリ 82,356 KB
実行使用メモリ 54,140 KB
最終ジャッジ日時 2025-05-14 12:59:56
合計ジャッジ時間 2,452 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge4
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ファイルパターン 結果
other WA * 37
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ソースコード

diff # 

# -*- coding: utf-8 -*-
import sys

def solve():
    # Read the integer I from standard input.
    # The problem constraints state that I will be an integer between 1 and 89 inclusive.
    # We can assume the input will be valid according to the constraints.
    I = int(sys.stdin.readline())
    
    # The problem asks whether tan(I degrees) is a rational number.
    # Let theta = I degrees = I * (pi / 180) radians.
    # Since I is an integer, theta is a rational multiple of pi.
    
    # There is a known result from number theory (related to Niven's theorem) which states:
    # If theta is a rational multiple of pi, then tan(theta) is rational if and only if
    # tan(theta) is equal to 0, 1, or -1.
    
    # We are given that the integer I is in the range [1, 89].
    # For angles I degrees in this range (which corresponds to the first quadrant, excluding 0 and 90 degrees):
    # - tan(I degrees) is always positive.
    # - tan(I degrees) cannot be 0 (since I is not 0).
    # - tan(I degrees) cannot be -1 (since tan is positive in the first quadrant).
    # - Therefore, the only possibility for tan(I degrees) to be rational is if tan(I degrees) = 1.
    
    # The equation tan(I degrees) = 1 holds if and only if I = 45 (within the range 1 to 89).
    
    # So, tan(I degrees) is rational if and only if I is exactly 45.
    
    if I == 45:
        # If I is 45, tan(45 degrees) = 1, which is rational.
        print("Yes")
    else:
        # For any other integer I between 1 and 89, tan(I degrees) is irrational.
        print("No")

# Call the solve function if the script is executed directly
if __name__ == '__main__':
    solve()
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