結果

問題 No.3032 ホモトピー入門
ユーザー qwewe
提出日時 2025-05-14 13:08:08
言語 PyPy3
(7.3.15)
結果
RE  
実行時間 -
コード長 2,884 bytes
コンパイル時間 205 ms
コンパイル使用メモリ 82,356 KB
実行使用メモリ 67,316 KB
最終ジャッジ日時 2025-05-14 13:09:32
合計ジャッジ時間 4,330 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample RE * 3
other RE * 37
権限があれば一括ダウンロードができます

ソースコード

diff # 

import sys

# Set input function to use sys.stdin.readline for potentially faster I/O
# compared to the built-in input() function, especially for a large number of lines.
input = sys.stdin.readline

def solve():
    # Read the number of pairs, N
    N = int(input())
    
    # Define characters for output using their ASCII values.
    # This is necessary because the problem statement forbids the use of
    # '<' and '>' characters directly in the source code.
    # ASCII 61 corresponds to '='
    # ASCII 60 corresponds to '<'
    # ASCII 62 corresponds to '>'
    char_eq = chr(61) 
    char_lt = chr(60) 
    char_gt = chr(62) 
    
    # Create a list to store the comparison result string for each pair.
    # Storing results and printing them all at once can sometimes be more efficient
    # than printing inside the loop, though for N <= 100 the difference is likely negligible.
    results = [] 
    
    # Loop N times to process each pair of integers (a_i, b_i)
    for _ in range(N):
        # Read the two integers a and b for the current pair from a single line of input.
        # map(int, input().split()) reads the line, splits it by spaces, 
        # and converts each part to an integer.
        a, b = map(int, input().split())
        
        # --- Comparison Logic ---
        # The core task is to compare a and b without using '<' or '>' operators.
        
        # Case 1: Check if a is equal to b. The equality operator '==' is allowed.
        if a == b:
            # If a and b are equal, append the '=' character to the results list.
            results.append(char_eq)
        
        # Case 2: If a is not equal to b.
        else: 
            # We need to determine if a < b or a > b.
            # We can use the property of integer division for positive integers:
            # Since a and b are guaranteed to be natural numbers (1 <= a, b <= 10^8),
            # the integer division `a // b` will result in 0 if and only if a < b.
            
            # Check if a < b using integer division.
            # Python's `//` operator performs floor division. For positive integers,
            # this behaves the same as truncation towards zero.
            if a // b == 0:
                # If a // b is 0, it means a < b. Append the '<' character.
                results.append(char_lt)
            # If a is not equal to b, and `a // b` is not 0 (meaning a is not less than b),
            # then it must be the case that a > b.
            else: 
                # Append the '>' character.
                results.append(char_gt)

    # After processing all pairs, print the results.
    # '\n'.join(results) concatenates all strings in the results list,
    # separated by newline characters, producing the required output format.
    print('\n'.join(results))

# Execute the main solution function when the script is run.
solve()
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