結果
問題 |
No.3033 エルハートの数え上げ
|
ユーザー |
![]() |
提出日時 | 2025-05-14 13:14:05 |
言語 | PyPy3 (7.3.15) |
結果 |
RE
|
実行時間 | - |
コード長 | 1,951 bytes |
コンパイル時間 | 328 ms |
コンパイル使用メモリ | 82,720 KB |
実行使用メモリ | 67,532 KB |
最終ジャッジ日時 | 2025-05-14 13:15:10 |
合計ジャッジ時間 | 2,847 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | RE * 3 |
other | RE * 20 |
ソースコード
import sys # Read the input values N, M, X from standard input. # N: The total number of people besides Alice. # M: The number of honest people among the N people. # X: The number of people Alice met. # The input values are expected to be space-separated integers on a single line. n, m, x = map(int, sys.stdin.readline().split()) # Calculate the total number of liars among the N people. # If there are N people in total and M are honest, the rest must be liars. num_liars = n - m # Determine the maximum number of liars Alice could have possibly met among the X people. # This number is limited by two factors: # 1. The total number of people Alice met (x). She cannot have met more liars than the total number of people she met. # 2. The total number of liars available in the population (num_liars). She cannot have met more liars than exist. # Therefore, the maximum number of liars she could have met is the minimum of these two quantities. max_liars_met = min(x, num_liars) # Calculate the minimum number of honest people Alice must have met. # To find the minimum number of honest people, we consider the scenario where Alice met the maximum possible number of liars. # If Alice met 'x' people in total, and the maximum number of them that could potentially be liars is 'max_liars_met', # then the remaining people she met must be honest. This gives the minimum guaranteed number of honest people. min_honest_met = x - max_liars_met # The problem asks if we can be certain that Alice met 3 or more honest people. # This certainty exists if and only if the minimum possible number of honest people she could have met is at least 3. if min_honest_met >= 3: # If the minimum guaranteed number of honest people is 3 or greater, we know for sure. print("YES") else: # If the minimum number of honest people could be less than 3 (i.e., 0, 1, or 2), # then we cannot be sure that she met at least 3 honest people. print("NO")