結果
| 問題 | No.2073 Concon Substrings (Swap Version) | 
| コンテスト | |
| ユーザー |  qwewe | 
| 提出日時 | 2025-05-14 13:20:11 | 
| 言語 | PyPy3 (7.3.15) | 
| 結果 | 
                                WA
                                 
                             | 
| 実行時間 | - | 
| コード長 | 1,391 bytes | 
| コンパイル時間 | 301 ms | 
| コンパイル使用メモリ | 82,952 KB | 
| 実行使用メモリ | 77,044 KB | 
| 最終ジャッジ日時 | 2025-05-14 13:21:04 | 
| 合計ジャッジ時間 | 4,136 ms | 
| ジャッジサーバーID (参考情報) | judge4 / judge5 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 5 | 
| other | AC * 17 WA * 20 | 
ソースコード
import sys
def solve():
    N = int(sys.stdin.readline())
    S = sys.stdin.readline().strip()
    # counts[group_idx][char_idx]
    # char_idx: 0 for 'c', 1 for 'o', 2 for 'n'
    counts = [[0, 0, 0] for _ in range(3)] 
    char_to_idx = {'c': 0, 'o': 1, 'n': 2}
    for i in range(3 * N):
        char = S[i]
        group = i % 3
        if char in char_to_idx:
            counts[group][char_to_idx[char]] += 1
    # U0: Max number of Type 0 "con"s.
    # A Type 0 "con" (S[j]='c', S[j+1]='o', S[j+2]='n' where j % 3 == 0)
    # requires 'c' from Group 0, 'o' from Group 1, 'n' from Group 2.
    U0 = min(counts[0][0], counts[1][1], counts[2][2])
    # U1: Max number of Type 1 "con"s.
    # A Type 1 "con" (S[j]='c', S[j+1]='o', S[j+2]='n' where j % 3 == 1)
    # requires 'c' from Group 1, 'o' from Group 2, 'n' from Group 0.
    U1 = min(counts[1][0], counts[2][1], counts[0][2])
    # U2: Max number of Type 2 "con"s.
    # A Type 2 "con" (S[j]='c', S[j+1]='o', S[j+2]='n' where j % 3 == 2)
    # requires 'c' from Group 2, 'o' from Group 0, 'n' from Group 1.
    U2 = min(counts[2][0], counts[0][1], counts[1][2])
    
    # The total number of "con"s, K = x0 + x1 + x2, is limited by N (K <= N).
    # Also, K <= U0 + U1 + U2 because x0 <= U0, x1 <= U1, x2 <= U2.
    # Thus, the maximum K is min(N, U0 + U1 + U2).
    ans = min(N, U0 + U1 + U2)
    
    print(ans)
solve()
            
            
            
        