結果
問題 |
No.1651 Removing Cards
|
ユーザー |
![]() |
提出日時 | 2025-05-14 13:24:12 |
言語 | PyPy3 (7.3.15) |
結果 |
TLE
|
実行時間 | - |
コード長 | 1,361 bytes |
コンパイル時間 | 283 ms |
コンパイル使用メモリ | 82,668 KB |
実行使用メモリ | 80,036 KB |
最終ジャッジ日時 | 2025-05-14 13:25:52 |
合計ジャッジ時間 | 9,087 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 12 TLE * 1 -- * 19 |
ソースコード
def solve(): K_val, Q_val = map(int, input().split()) results = [] for _ in range(Q_val): N_orig = int(input()) if N_orig <= K_val: results.append(N_orig) continue # Calculate s: number of steps s = 0 current_N = N_orig while current_N > 1: if current_N <= K_val: s += (current_N - 1) current_N = 1 # To exit loop else: # current_N > K_val removed_count = (current_N - 1) // K_val + 1 current_N -= removed_count s += 1 # Calculate ans based on s steps ans_val = 1 if K_val == 1: # Constraint K >= 2, so K-1 >= 1 # This case should not be reached. If it were K=1, all cards but one might be removed. # Or if N_orig > 1, all cards are removed. This case is ill-defined for K=1. # Since K >= 2, K-1 >= 1. pass for _i_step in range(s): # ans_val_minus_1 = ans_val - 1 # term_to_add = ans_val_minus_1 // (K_val - 1) # ans_val = ans_val + 1 + term_to_add ans_val = ans_val + 1 + (ans_val - 1) // (K_val - 1) results.append(ans_val) for res in results: print(res) solve()